Can you construct a linear function $L: \mathbb{R}^3 \rightarrow \mathbb{R}$ such that $L\left(\begin{array}{r}1 \\ -1 \\ 0\end{array}\right)=1, L\left(\begin{array}{r}1 \\ 0 \\ -1\end{array}\right)=4$, and $L\left(\begin{array}{r}0 \\ 1 \\ -1\end{array}\right)=-2$ ? If yes, find one. If not, explain why not.