00:01
In this problem, we have a barge in the canal.
00:02
The water in the canal away from the barge is moving at 1 .5 meters per second.
00:09
And we're given a bunch of dimensions of the canal and the barge.
00:13
We've got a picture here, and what we really want is a front view here of the canal and the barge, because this is the cross -sectional area through which the water is flowing.
00:25
We know that the flow rate in has to be the flow rate at point a and has to be equal to the flow rate at point b.
00:36
We're asked about the velocities at a and b, so most of it is going to be finding the area, cross -sectional areas at point a and b.
00:45
The flow rate in the canal away from the barge is the area of the barge times the velocity.
00:54
The flow rate at point a is the cross -sectional area at point a times the velocity of point a.
01:01
And at point b is the cross -sectional area at b times the velocity of b.
01:07
So we have everything for the flow rate away from the barge.
01:11
That's just d times h, bn.
01:17
Now, we need the area at cross -section a...