00:01
Okay, so for this question, they want us to determine the decay constant in seconds, and they tell us that we have carbon 14 with a half -life of 5 .73 times 10 to the three years.
00:18
Now, the equation that we need to solve this question is t -half -life, t -half, so it goes 0 .693 over k, which is the decay constant.
00:28
Now, they want us to find k, so let's isolate k.
00:30
So if you multiply k on both sides, we get k times it by the half -life is equal to 0 .693.
00:43
Now we divide both sides by the half -life.
00:48
And we get k is equal to 0 .693 over the half -life.
00:56
Now let's plug in the numbers...