Question
Carbon and oxygen are known to form two compounds. The carbon content in one of these is $42.9 \%$ while in the other it is $27.3 \%$. Show that this data is in agreement with the law of multiple proportions.
Step 1
In the first compound, the percentage of carbon is $42.9\%$. Therefore, the percentage of oxygen must be $100\% - 42.9\% = 57.1\%$. Show more…
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Carbon combines with oxygen in a mass ratio of 1.000:2.664 to form carbon dioxide $\left(\mathrm{CO}_{2}\right)$ and in a mass ratio of 1.000: 1.332 to form carbon monoxide $(\mathrm{CO})$. A third carbon-oxygen compound, called carbon suboxide, is $52.96 \%$ C by mass and $47.04 \%$ O by mass. Show that these compounds follow the law of multiple proportions.
Consider 100.0 -g samples of two different compounds consisting only of carbon and oxygen. One compound contains 27.2 $\mathrm{g}$ of carbon, and the other has 42.9 $\mathrm{g}$ of carbon. How can these data support the law of multiple proportions if 42.9 is not a multiple of 27.2$?$ Show that these data support the law of multiple proportions.
Consider 100.0 -g samples of two different compounds consisting only of carbon and oxygen. One compound contains $27.2 \mathrm{g}$ of carbon and the other has $42.9 \mathrm{g}$ of carbon. How can these data support the law of multiple proportions if 42.9 is not a multiple of $27.2 ?$ Show that these data support the law of multiple proportions.
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