0:00
Hi, everybody.
00:01
So find the exit temperature and the total entropy generation per mole of exit mixture.
00:06
Okay? so the mole ratio is going to be 2 to 1.
00:15
N2 over n1 is 2 to 1.
00:19
So there is no external heat transfer.
00:24
So we have q equals 0 and no warp transfer.
00:28
So your work is going to also be 0.
00:31
And so your continued equation is n2 plus n1 equals n3.
00:38
As you see is, you can be 2 plus 1 equals n3.
00:46
So this is going to be n1 and it's going to be n1 and 1 here.
00:51
N1 equals n3.
00:55
Okay.
00:56
So your energy, and i'll put energy equation here, it's going to be n1h1 plus n2h2 equals n3h3.
01:11
And we get n1h1 plus 2n1h2 equals 3n1h3.
01:21
Now we have n1h1h1 plus 2h2 equals 3n1h3.
01:31
Okay and um so now we have using the energy um equation we have h1 plus 2h2 equals 3h 3 because you're in here cancels l okay and um so now we're just going to assume so now we have h equals 8 equals h -5 -4 plus c -p of t minus 540.
02:15
And similarly manually, we can apply the relation to energy equation, okay? so c -p -n -2, t -1 minus 540, plus t times c -o2 times t2 minus 540.
02:36
Equals 3 cp mix times t3 minus 540.
02:45
I'm just going to like use that so we can use apply this to this here.
02:53
So now we need to figure out what cp is.
02:56
So just let me do another squiggly lines.
02:58
You know it's separate.
03:00
And we at cp, it's going to be one third times 28 .01.
03:09
Plus two -thirds times 44 .01 times 0 .201.
03:18
This is 8 .224.
03:22
Okay.
03:24
Now we can do back to the school line...