00:01
For this problem, we want to find how many grams of co2 are produced per year by the entire human population, given that each person consumes 5 .10 to the 2 grams of glucose a day, and that the human population is 6 .5 billion.
00:22
So the first thing that we want to do is we want to relate this glucose sample to co2.
00:29
And so the first thing that we're going to have to do is we're going to have to run.
00:32
Write that chemical equation for the combustion reaction of that in order to find the multiple ratio of carbon dioxide to glucose.
00:41
So we know the chemical formula for glucose is c6, h12 -06.
00:48
You know that our reactant is going to be o2, and we know that our two products are going to be h -2 and co2.
00:56
Now we want to balance this.
00:57
So we first look to our first element, which is carbon.
01:00
We have six on the left, but only one on the right to make it balanced.
01:04
Put a six here, so i have six on both sides.
01:07
Now we look at the hydrogen.
01:09
We have 12 on the left, two on the right, so to make 12 on both sides, put a six there.
01:15
Now we look to the oxygen.
01:17
We have 6 oxygen from the h2o and 12 oxygen from the co2.
01:21
And we have 6 oxygen here on the left hand side from the glucose.
01:27
So we're missing 12 oxygen.
01:29
So to make up the 12 oxygen, i'm just going to put a 6 in front of the co2.
01:33
So we get that our final balanced chemical equation for the combustion of glucose is c6h1206 plus 602, yields 6h22 plus 6 co2.
01:49
So now we know that for every mole of glucose that we get 6 moles of co2, and that's going to be very important information when it comes to calculating our final answer.
02:00
So we know that 6 to 1 is our ratio.
02:07
We want to find the molar mass of glucose and the molar mass of co2, which are two main substances, so that we can do some basic calculations.
02:16
So let's do glucose first.
02:20
C6 h1206.
02:21
So we have six carbons, which is 12 .01.
02:26
And then we have 12 hydrogens, each of which are 1 .008.
02:31
And then finally, we have six oxygens, which are 16 .00...