Question
Carbon disulfide has a vapor pressure of 363 torr at $25^{\circ} \mathrm{C}$ and a normal boiling point of $46.3^{\circ} \mathrm{C}$ . Find $\Delta H_{\mathrm{vap}}$ for carbon disulfide.
Step 1
The formula to convert Celsius to Kelvin is $K = C + 273.15$. So, $T_1 = 25^{\circ}C + 273.15 = 298.15 K$ and $T_2 = 46.3^{\circ}C + 273.15 = 319.45 K$. Show more…
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