00:01
Alright, so here is the problem 108 in chapter 19, and this question are going to ask various questions about carbon disulfide.
00:11
Part a is asking us to draw the lewd structure of this molecule, cs2.
00:19
So the lewd structure of cs2 will look like this.
00:24
Carbon as the center atom and sulfur around carbon.
00:29
So carbon has two of four valence electrons and sulfur will have six.
00:35
So as a result, one, two, three, four, five, six, one, two, three, four, five, six.
00:43
So these two electrons bond together and this bonds together.
00:51
So there are two pairs of double bond between c and s.
00:56
So what do you predict the bond order of cs bond? in this case, the bond order of c and s will be part b.
01:12
Use the vs epr method to predict the structure of cs2 molecule.
01:17
So from the fluid structure above, we can see that the central atom c is bonding with two sulfurs, and there are no long pairs of electrons around the carbon.
01:33
So according to the vs epr mode, this is a linear structure.
01:48
Now we look at part c.
01:51
Liquid c .s2 burns in oxygen with a blue in fame, forming co2 gas and so2 gas.
01:59
Write the balance equation for this reaction.
02:03
So we have c .s2 liquid, burns in water, burns in oxygen, so it reacts.
02:12
With oxygen and result in co2 and so2.
02:23
So oxygen is a gas, co2 is a gas, so2 is a gas, co2 is a gas, so2 is a liquid.
02:31
So looking at the carbon, carbon, 2s, 2, so2, so there are two oxygens, 2 to 4, 6 oxygens in total, so there's a 3 before the oxygen.
02:45
So this will be the balanced equation for part c.
02:54
Now let's look at the question d.
02:58
Using the data in the table and in the appendix c, calculate delta h and delta g.
03:07
So after the calculation, we also need to determine the reaction is it endothermic or exothermic, and whether it's spontaneous or not.
03:18
So to calculate delta h values of the reaction, that will be the delta h formation of the products minus the delta h formation of the reactants.
03:33
So it will be equal to the delta h0 of carbon dioxide gas plus two times the delta h0 of so2 gas minus the delta h0 of cs2, liquid minus 3 times of delta h0 of oxygen gas.
03:59
So this number is equal to negative 393 .5 plus 2 times negative 296 .9 minus 896 .9.
04:19
So by doing the math, we will get a number delta h0 equal to negative 1077 kilojoules.
04:35
So then we calculate for delta g0 of the reaction.
04:40
That will be the delta g0 of the products minus the delta g zero of the reactants.
04:47
So the products are co2 gas, two times the delta g0 of so2 gas minus delta g0...