00:01
In this problem, we are told that carnobo wax is an ester that is formed between a c -32 straight -chain alcohol and a c -20 straight -chain carboxylic acid.
00:12
We need to draw out the structure of carnabalax from this information, and we can begin by drawing out the two structures that we are told that react together to form that ester.
00:24
So in each case, we start with the given functional group.
00:30
So for the c -32 straight -chain alcohol, alcohol is that functional group.
00:34
So that's corresponds to that oh.
00:37
And the 32 just means that there are 32 carbons in that structure.
00:40
So we can count all of those carbons out.
00:44
So you get 32 in that structure.
00:46
And so that's what the c -32 straight -chain alcohol molecule looks like.
00:53
And now for the c -20 carboxylic acid, the carboxylic acid functional group is defined by that c -o -o -h.
01:01
And again, the c -20 just means that there are 20 carbon atoms in that structure.
01:08
And so now that we have drawn out what both of those would look like, if we line them up so that we react, starting from the left, with this terminal oh group from the carboxylic acid, we can have, recalling that the functional group for an ester has the general formula of r -o -o -r, where one of the o's is part of a c -d -bond o, the other one is directly bonded to that c -dobond o and another functional group to form an ether, and we can see condense this formula to be c -o -2 for an ester.
01:57
And so keeping that in mind, again, if we start with the c20 carboxylic acid, and at the very far right end of that structure as we drew it out, we have that carboxylic acid functional group, and everything to the left of that is just that long carbon chain, and we react that with the terminal oh group from the alcohol.
02:21
So in the far left, based on the way that we drew it out, we have that oh group and everything to do that...