00:01
So we're looking at the mean wait time, and we are going to be assuming that the mean wait time is eight minutes, and alternately that it's different.
00:15
So that's part a.
00:18
Now, they take a sample, and we know that the sample is 120 people, and we know that the x bar they get for that is 8 .4 minutes.
00:29
We are to assume that the population standard deviation is 3 .2 minutes.
00:37
Now, regardless of the shape of the distribution, and let me just do this, regardless of the shape of the distribution, the sampling distribution is going to be approximately normal because of the central limit theorem.
00:50
And the central limit theorem, if we take, we're going to assume that this is the mean is 8, and we're going to have that the standard deviation of the x bars all coming from a sample sizes of 120 is equivalent to 3 .2 divided by the square root of 120.
01:07
So we want to find what's the likelihood if the mean is actually 8.
01:14
Excuse me, 8, that we would get an 8 .4 or higher, or this is 0 .4, 7 .6 or lower.
01:24
And these two together will be our p value.
01:27
So let's find that probability.
01:28
So what's the probability of getting an x bar that's greater than or equal to 8 .4 in our picture? and then we'll double it since we want both ends for our p value.
01:39
And we'll convert this to a z because we know our population standard deviation.
01:45
And so we have 8 .4 minus 8 divided by that 3 .2 over the square root of 120.
01:52
And be careful about the way you put that in your calculator.
01:55
I know my numerator is 0 .4 and then divided by left -hand parentheses, 3 .2 divided by the square root of 120.
02:06
And let me get that answer.
02:09
And i get that that z value comes out to be 1 .3693.
02:17
And it keeps going on.
02:19
You may round that off to 1 .37 if you're going to be using a table in the book.
02:24
I'm going to use my normal cdf button.
02:27
I don't even have my table out here.
02:29
And i don't have a copy of the book.
02:31
My lower limit if i use normal cdf is that number that we just got here.
02:37
And my upper limit i'm just going to put in as like a thousand and leave the mean at zero and one for the standard deviation.
02:44
And when i do that, i get 0 .085...