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$\cdot$ A certain digital camera having a lens with focal length 7.50 $\mathrm{cm}$ focuses on an object 1.85 m tall that is 4.25 $\mathrm{m}$ from the lens. (a) How far must the lens be from the sensor array?(b) How tall is the image on the sensor array? Is it erect or inverted? Real or virtual? (c) A SLR digital camera often has pixels measuring 8.0$\mu \mathrm{m} \times 8.0 \mu \mathrm{m} .$ How many such pixels does the height of this image cover?

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a) $\therefore$ The photocells must be $[7.63 \mathrm{cm}]$ from the lensb) $\therefore$ Height of the image is $[3.32 \mathrm{cm}]$ Because $y^{\prime}$ is negative, the image is linverted $]$ and $[$ real $]c) $=4.15 \times 10^{3}$ pixels

Physics 102 Electricity and Magnetism

Physics 103

Chapter 25

Optical Instruments

Electromagnetic Waves

Reflection and Refraction of Light

Cornell University

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

Hope College

Lectures

02:30

In optics, ray optics is a geometric optics method that uses ray tracing to model the propagation of light through an optical system. As in all geometric optics methods, the ray optics model assumes that light travels in straight lines and that the index of refraction of the optical material remains constant throughout the system.

10:00

In optics, reflection is the change in direction of a wavefront at an interface between two different media so that the wavefront returns into the medium from which it originated. Common examples include the reflection of light, sound and water waves. The law of reflection says that for specular reflection the angle at which the wave is incident on the surface equals the angle at which it is reflected. Reflection may also be referred to as "mirror image" or "specular reflection". Refraction is the change in direction of a wave due to a change in its speed. The refractive index of a material is a measure of its ability to change the direction of a wave. A material with a higher refractive index will change the direction of a wave to a greater degree than a material with a lower refractive index. When a wave crosses the boundary between two materials with different refractive indices, part of the wave is refracted; that is, it changes direction. The ratio of the speeds of propagation of the two waves determines the angle of refraction, which is the angle between the direction of the incident and the refractive rays.

02:59

A certain digital camera h…

03:06

A camera lens has a fixed …

06:07

02:33

(a) An object 34.5 $\mathr…

03:24

($a$) An object 37.5 cm in…

01:29

A person 1.70 m tall is st…

01:51

A lens for a digital camer…

03:13

A camera with a 50.0 $\mat…

05:32

Camera A camera with an $8…

05:37

A diverging lens has a foc…

06:15

04:25

A common zoom lens for a d…

05:34

All right. So the question one was asking us all four months of the lands before on the sensory. Okay, So is actually just asking us the image distance? OK, which is the V here? So when we know that one of our focal lens you so you go to one over image distance, Mind as well over object is so if we do sound duration, we get that B, which is the image distance is simply equal to youth. Has f over U plus f you which is the object instance. The skin has 4125 meter and half is the focal lenses. Give a 7.507 year, which means that the image distance is equal to you has F which is 4125 times 10 to about two centimeter times 7.50 centimetres over 4.25 has tension about part of a two centimeter plus 7.50 centimeters and this will give us the image. Distance is equal to 7.63 centimeter. We'll question be It was asking us how tall is the image on a sensory? So is the heist My image So we know the formula for him, like magnification is equal minus the image distance over rain object ISMs, which is equal to the hide of image over the actual heights. Okay, if it was, an arrangement will get why prime was the high image is equal to minus we times. Why over you. Okay? And we don't need, um, actual high book actualize giving us 1.85 meter. So if we plugging will get why Prime is equal to minus B, which is 7.63 centimeter times 1.85 meter, which is 1.85 times 10 to pope. Two centimeter divided by you, which is object distance schema is 4.2 by times since the IPO to centimeter, which will give us minus three point 32 centimeters. Call the image for your high. The image. Okay. And for the last question, it was asking us how many such pixels does the height of this image cover? Okay. And this is the equations for the numbers of pixels, which is an equal to y pry over l. Why price? The hind off image and that is the size of the um, no pig. So Okay, so we know that why? Prime is giving us 3.32 times. I'm sorry. 3.32 centimeter, which is three point during two times 10 to a power 92 meter and the size of the pixels. A four year old micro meter, which is a point old times 10 to the power off 96 meter. And this will give us the number of pixel is equal to 4.1 by times potential power of three. Okay, as I actually forgot something for the question to I forgot to explain to you guys that is the M Israel or in a virtual or is Iraq You murdered so well from here? You see, that seems the white price equal to minus 3.3 to send a mere since this is an active that Mrs Environment and just this very limits is really okay. So he's our solution for the question and

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