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$\cdot$ A coyote chasing a rabbit is moving 8.00 $\mathrm{m} / \mathrm{s}$ due east atone moment and 8.80 $\mathrm{m} / \mathrm{s}$ due south 4.00 s later. Find (a) the $x$and $y$ components of the coyote's average acceleration during that time and (b) the magnitude and direction of the coyote's average acceleration during that time.

a) $-2.20 \mathrm{m} / \mathrm{s}^{2}$b) $47.7^{\circ}$

Physics 101 Mechanics

Chapter 3

Motion in a Plane

Physics Basics

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

University of Washington

Simon Fraser University

Hope College

Lectures

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So we have a coyote, the ex initial 8.0 meters per second and then we have a V Y national equaling zero meters per second. We're going to say north and east are positives. Western south are negative and so we can save the Y. Final is going to be equal. Teo Ah, negative 8.80 meters per second and then we're going to save the X final Equal zero. So he's running due east and then he stops, pivots and is traveling neg negative 8.8 meters per second. The time it takes to change his velocities is going to be 4.0 seconds. So, essentially, what is his acceleration? The magnitude of his acceleration, vector and his that and the direction of his acceleration factor. So we can say that the ex component of the acceleration will be the X final Ah, minus VX initial divided by Delta t. So for so this is equaling negative two meters per second squared and then a Ah, the white component of acceleration will simply be v y final Ah minus view initial divided by again for the change in time. So this will be negative. 2.2 meters per second squared. And so the magnitude of the acceleration factor will be equal. Teo Negative two squared plus. And if 2.2 squared all to the 1/2 power and this is equaling two point not oh, brother, 2.97 meters per second squared. Yeah, and then Seita is going to be equal to our 10 of a native to 0.2 divided by negative too. So you simply have the white component of exploration divided by the ex component of acceleration. And ah, this Fada is going to be equal to 13. Oh, rather, 47.7 degrees. My apologies. And again, we have a negative x a negative X A negative. Why? Therefore, we're in the third quadrant so we can say 47.7 degrees south of west. So this would be your direction. And then this would be your magnitude of the exploration vector. That is the end of the solution. Thank you for watching

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