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$\cdot$ A jet makes a landing traveling due east with a speed of 70.6 $\mathrm{m} / \mathrm{s}$ .If the jet comes to rest in 13.0 $\mathrm{s}$ , what are the magnitude and direction of its average acceleration?

$-5.43 \mathrm{~m} / \mathrm{s}^{2}$

Physics 101 Mechanics

Chapter 2

One-Dimensional Kinematics

Motion Along a Straight Line

University of Michigan - Ann Arbor

University of Sheffield

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So in this problem, we have a jet traveling to east with initial velocity off 70.6 meters or second. And the jet comes to rest after a time off. 13 seconds. And the problem wants to know where is the magnitude and the direction off their acceleration. Okay, well, are we going find out this. We know there is this recreation. It describes the velocity of a particle with respect the time and disintegration. These vehicles v zero plus a t. Okay. What is the final velocity? Your final velocity. Zero. Because the jets stop the initial velocity. 70.6 plus acceleration times 13. It was the time. So the acceleration is going to be minus 70.6. Divided by 13. This is it to minus five point 43 meters. Her second square. Okay, so what is the magnitude? Magnitude is the positive value off the acceleration. So reciting the magnitude is 5.4. Sorry, I'm a mess in here, 5.4 three meters per second squared. And the direction? Well, we know that a negative acceleration means that he's opposite to the movement off their object. So if it's opposite of the movement in the jet. Rhys Traveling east. The direction? Yes. Die. Direction is west. Okay, so this is the final answer. Thanks for watching.

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