cdot-a-jet-makes-a-landing-traveling-due-east-with-a-speed-of-706-mathrmm-mathrms-if-the-jet-comes-t

Question

$\cdot$ A jet makes a landing traveling due east with a speed of 70.6 $\mathrm{m} / \mathrm{s}$ .
If the jet comes to rest in 13.0 $\mathrm{s}$ , what are the magnitude and direction of its average acceleration?

Nathan Silvano · Accepted Answer

So in this problem, we have a jet traveling to east with initial velocity off 70.6 meters or second. And the jet comes to rest after a time off. 13 seconds. And the problem wants to know where is the magnitude and the direction off their acceleration. Okay, well, are we going find out this. We know there is this recreation. It describes the velocity of a particle with respect the time and disintegration. These vehicles v zero plus a t. Okay. What is the final velocity? Your final velocity. Zero. Because the jets stop the initial velocity. 70.6 plus acceleration times 13. It was the time. So the acceleration is going to be minus 70.6. Divided by 13. This is it to minus five point 43 meters. Her second square. Okay, so what is the magnitude? Magnitude is the positive value off the acceleration. So reciting the magnitude is 5.4. Sorry, I&#x27;m a mess in here, 5.4 three meters per second squared. And the direction? Well, we know that a negative acceleration means that he&#x27;s opposite to the movement off their object. So if it&#x27;s opposite of the movement in the jet. Rhys Traveling east. The direction? Yes. Die. Direction is west. Okay, so this is the final answer. Thanks for watching.

Nathan Silvano · Answer

Okay, So in this problem we have a jet traveling south with initial velocity off 71 0.4 meters per second and he stops after a displacement off. Let&#x27;s see nine or nine meters. But this is information we have. The problem wants to know what is the magnitude and the direction off the acceleration. Okay, so always remember to look to what we want and what we have. We want to discover acceleration. So we need to use the equation has acceleration, but we only have velocity and displacement. So the equation we&#x27;re going to use needs to contain velocity displacement and they resist equation that contains exactly this went it is such a question is V squared equals two. The zero square waas too. I&#x27;m say times displacement. This is recreation. We&#x27;re going to use immigration that describes the velocity off object with respect with the displacement. So let&#x27;s see what is vey these zero. Because the jetstop zero equals two vizier square that is 71 point for square Hawass two times 949 times. Just release mint. Sorry. Time&#x27;s a celebration times acceleration that we want to discover. So let&#x27;s see, we have here minus 5000. Nice seven 0.96 equals two When. 1000 h on Drea 98 A. It is really bad. Let&#x27;s see. Okay, So what is the acceleration? Acceleration is minus 1009. 7.96 divided by one 89 eight. This is something around minus two points. 68 meters or second scratch. So what is the answer? The quest. The problem asks us about the magnitude off the celebration. Magnitude is always the positive value. So the magnitude is positive. Two points, 68 meters per second squared. And what is the direction? Well, we find out solving a problem. That acceleration is negative. So if the acceleration is negative, that means he isn&#x27;t cheese in the opposite direction off the movement. And if the movement of jet was self, the direction of the exploration only can be not. Not. Okay, so this is the final answer. Thanks for watching North

Julie Farhm · Answer

in this problem. We&#x27;re told that the jetliner hits the runway with an initial speed of 69 meters per second and within the length of the 750 meter long runway. It has a final speed of 6.1, so it needs to be able to decelerate or negatively accelerate in the displacement within a displacement of 750 meters, such that it can be going 6.1 meters per second at the end, so we can use the expression Um V squared is equal to initial velocity squared, plus two times acceleration times the distance. This expression is handy when we are not given information about the time, so 6.1 meters per second were to square. That quantity is equal to 69 meters per second, also squared, plus two times the acceleration which we don&#x27;t know times the displacement of 752. Rearranging that equation. I&#x27;m not solving anything yet, just moving the terms around, just going to subtract 69 liters per second from both sides and then that&#x27;s going to equal two times 7 50 times a cell. Just divide by two times 7 50 and that gives us an expression for a still plugging those numbers. In the calculator. We have an acceleration of negative 3.15 meters per second squared and rounded to two significant figures that would be negative 3.2 meters per second squared. The negative sign indicates that the the jetliner&#x27;s moving in the positive direction, which I&#x27;ve drawn on my picture to the right. The acceleration is opposing that directions of the acceleration is to the left.

Nathan Silvano · Answer

so in problem dirty we have Ah 7 47 that reaches its takeoff speed off one 156. My owes our in just 35.2 seconds. Okay, The problem wants to know what is Thio Average acceleration off the problem off the airline. And we know that average acceleration is determined by the velocity divided by the time. The only problem is our velocity is in miles per hour. We need took over two meters per second. There is a way to do this. Let&#x27;s see, we can just for miles per hour, four meters per second. We just need to divide by 2.2 three seven. So we have one 56 divided by two points to 37 This is something around 17 medias or second. So our final answer it&#x27;s going to be acceleration. It goes to 70 meters per second, divided by 35.2. This is equal to two meters per second square. That&#x27;s the final answer for this question. Things were watching

Mayukh Banik · Answer

so the velocity of the air is in north east direction. So the horizontal component is three a over route to and the vertical company It is v A over to So doesn&#x27;t velocity of the plane with restaurant the ground? It was velocity of the played in still air plus velocity off the ear and is a vector some. So from here we could find that with us be of the they just make the ground with them out to be, since the velocity of the plane is in the north. So that&#x27;s that without skipped a plane. So they speak arms V A over you do square does V a over route to cast a VP squared my road. He was 65 over route do 65 over route to the US Phoebe east to 35 squared. Give me that by our and that comes out to be 1 18 Uh, that to be 1 94 Why? In 53 you help me. Our

Vishal Gupta · Answer

in the even problem. You&#x27;re different Velocities. Oh, an airplane are given at two different times. So do we present these Ruskies stuff on the drop? The directions in the terms off. No southeast and vest And the direct shoes are sure like this Not so eased. Invest No, the velocities. The initial velocity is given as 1 92 kilometer. Per Are do you not? Yes, it is like this was this Carol is representing 1 90 No kilometer, but, uh, from Oh, do a no. After three hours, the new velocity is do for particular meter. Per are in Northwest direction Means from north to vest at an angle of 45 degree. Say this. So these are that who velocities Is this from O. B? And it is proof or a kilometer? Well, uh, this is assumed as the one and this It says you, Toby, they do. This is the first part off the question. No. For the second part, we have to find the change in the velocity that the change in velocity will be given as the difference in final velocity. The initial velocity. So to find this change in velocity, we will complete a parallelogram with the help off these two vectors taking these two raptors esta and just in size off the battleground. So here we complete this paragraph one side, this and an end of this. This is the pattern camp which we complete it. So the Dagnall off this battle of around starting from the tip off, even the tip off the to we give us the change in velocity means that difference off V two and V even this we give us the value off change in velocity. So the angle between these reactors is 45 degree. As for s, the magnitude of this difference is concerned. You simply apply trying the law, the tradition which is equally applicable on subtraction also, And according to it, the folder will become even elsewhere. Last videos where minus move, even veto costs. Tita, the angle between the vectors and here it is. 1 92 slip plus 2 40 Slip minus two into 1 92 2 40 into co sign off. 45 degree so unique square off these vectors. So first of all, the sled off 1 92 gives us her is 6000 864 plus the square off who 40 gives us 57,000 600 minus. Now the product off these four terms most ofall cost 40 degree will be one of one route to it was 45 degree then into 2 40 into 1 92 and indeed to it becomes six. 65,000 1 66 0.96 overall iffy ed and subject the stones 36,000 864 less 57,000 and 600 minus 65,000 166 0.296 We get 29,000 297.30 four The low meter are finally. If we make the square root this term, we will get the slab Hoot Oh, 29,000 to 97.4 will give us 171 wind 16 The long meter for our Which is the Magne dude off changing velocity? No, we need to find yes and then also to suppose you find it&#x27;s angle with this line most of all, the draw horizontal baseline on this starting from here this the angle above this line will be 45 degree and this portal angle. If you want to find out, let us say it. L far then that value the formula for this Daniel probably become the central we are finding with the vector veto. So the form that will be the one sign Tita on even minus veto This will be Nieto minus V one, cause Tina, we use this formula. So then l far is equal to even signed Tita divided by V Tu minus We&#x27;ve been Cost Eater Meet U minus even osteo. You know, we&#x27;ve won Waas 1 92 into sign 45 degree the 2 to 40 minus 1 92 Because 45 degree means in the numerator I will have signed 45 into 1 92 which becomes 1 35 Boeing 76 in the denominator this is this will be seen a sign 45 cost 45 will be having same values toe 1 35 point 76 So I really yet through 40 minus 1 35 176 We give me 104 going to four. And after solving it 1 35 0.76 divided by Ponzi before going to four. This is 1 35.76 divided by 104 0.24 gives us 1.302 So l for will become 10 inwards 1.302 which is equal toe 50 do 0.47 degree this complete angle. So if I want to find out this single only if we knew 45 degree less. So the random Peter, if I see will be 50 to 14 73 minus 45 degree which comes out of the seven point for seven degree from the direction is this is so all vest So off vest, this is the final loss. This is the change in velocity was marinated You&#x27;re is 1 71.16 kilometre para and direction ist 7.47 degrees south or west. No, the acceleration. If I want to find out, it will become Delta V by delta T and Delta T is three hours certain become 1 71.16 divided by three kilometre for our and are so I get acceleration s 1 71 mind 16 divided by three and it is 57.5 kilometer are square and the direction with women Same is 7.47 Devery south off this.

Problem

$\cdot$ A car is traveling due north at 23.6 $\ma…

Problem 32 Easy Difficulty

$\cdot$ A jet makes a landing traveling due east with a speed of 70.6 $\mathrm{m} / \mathrm{s}$ .
If the jet comes to rest in 13.0 $\mathrm{s}$ , what are the magnitude and direction of its average acceleration?

Answer

$-5.43 \mathrm{~m} / \mathrm{s}^{2}$

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