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$\cdot$ Calculate the net torque about point $O$ for the two forces applied as in Figure $10.42 .$ The rod and both forces are in the plane of the page.

28 $\mathrm{Nm}$

Physics 101 Mechanics

Chapter 10

Dynamics of Rotational Motion

Newton's Laws of Motion

Rotation of Rigid Bodies

Equilibrium and Elasticity

University of Michigan - Ann Arbor

Simon Fraser University

Hope College

University of Winnipeg

Lectures

02:34

In physics, a rigid body i…

02:21

In physics, rotational dyn…

0:00

Calculate the net torque a…

04:34

$\bullet$ Calculate the to…

16:06

Calculate the torque (magn…

01:08

Calculate the torque of th…

06:20

Calculate the net torque (…

02:18

$\bullet$ In Figure $10.44…

03:34

A Couple. Two forces equal…

02:12

In Fig. E10.7, forces $\ve…

03:15

08:25

Two forces equal in magnit…

02:31

The fishing pole in Figure…

02:01

Find the magnitude of the …

01:38

SSM ILW The body inFig…

01:30

02:25

Determine the torques abou…

00:42

01:01

01:11

00:35

So here we can say that the torque is going to be equal to the forest times the length from the center of Mass and the length is going to be equal to our sign of theta. So. And if we choose counterclockwise to be positive, we can say that torques of one is going to be equal to force of one length sub one, and this would be equal to negative eight times five. So this would be negative 40 noon meters and then torques of two. But vehicle to out F sub to Elsa, too, and this would be equal to 12 times to sign of 30 degrees. This would simply simply be equal to positive 12 new colors. So when we find the sum of torques, this is simply going to be talks of one plus talks up to, and this will be negative 40 plus 12. And this is equally negative 28 Newton meters. So this would be your final answer, however, because it's negative and we chose counterclockwise to be positive. This would be this would produce clockwise rotation. Yeah, that is the end of the solution. Thank you for watching

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