Problem

$\cdot$ $\cdot$ A boxed 10.0 kg computer monitor …

05:36

Problem 10 Medium Difficulty

$\cdot$ $\cdot$ A tow truck pulls a car 5.00 $\mathrm{km}$ along a horizontal road-
way using a cable having a tension of 850 $\mathrm{N}$ (a) How much
work does the cable do on the car if it pulls horizontally? If it
pulls at $35.0^{\circ}$ above the horizontal? (b) How much work does
the cable do on the tow truck in both cases of part (a)? (c) How
much work does gravity do on the car in part (a)?

Answer

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Physics 101 Mechanics

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Video Transcript

We know that when the tow truck is pulling the car horizontally on DH, there's a displacement. We can say that the work done is the northerners F times as times cause I'm fight where f is the force is the displacement, and five is the angle that it's the force and the displacement are making. So, for example, when we're dealing with a tow truck pulling the car, horizontal leaders no direction, there's no angle that the force is making to the displacement. Then we see that if forces along the horizontal, the displacement will be on the scene direction. That means the angle between the force and the displacement will be zero. So that makes co sign. Fi equals one because called co sign zero is one, and the equation changes toe. So let's call it zero f times s. Similarly, when there's an angle, so lets a. Now the force is making an angle 35 degrees, then the force and the displacement has an angle between them, which is 35 degrees. So call sign. If I will not be a CZ one anymore, it will be coastline 35 degree in whatever the value that cause interrogative has the nearly question will be, Let's call it doubly certified because there's a very high degree angle and we'll have a force times the displacement times cause I'm 35 degrees. So in part A, we need to find out the world than due to the tow truck pulling the car. So the work done on the truck will be f times S s. So the displacement is five times and were three meter and ah, worked on are the forces eight fifteen 15 Newton ts. And as we mentioned, that co sign will be zero if that's pulled horizontally. So we'll have 4.25 times tent bar. Six Jules. Similarly, when it's cold at 35 degree angles about the horizontal and we'll have cosign terrified decrease. But the rest of the numbers will be seen. The final answer, or final worked on will be 3.48 times into the air. Six. Jules, now in Part B. We need to find out the work done on the car. So for that case, we see that due to the tour truck, we had a displacement. So let's say the displacement is from right to left and the force due to talk truck. When it was Horace under, it was on this direction. So the anger off the force and the displacement due to car will be 1 80 degrees because they're the force on the car will be up in the opposite direction off the fourth. That's when apply due to the Toyota, so we'll have an angle of 1 80 degrees now instead of zero. So we know that cause I in 1 80 degrees is equal to negative cause I kn Cyril agrees, which is negative one. So that means for the for the horizontal case, the work done due to the car will be negative. 4.25 times tend bar six years so worked on due to the car our work done on the heart for the horizontal force. You're the car with the negative UH, 4.25 times 10 to the 46 shoots. Similarly, when there's when the force is making an angle from the horizontal, which was 35 degrees, then the angle it makes ah do you do to the opposite side will be 1 80 degrees minus 35 degrees, which is 1 40 five degrees, and we know that call sign off. 1 45 is negative. Call sign off 35 degrees. So the work done on car will be, uh, it's actually call it 1 45 negative. Three or in 48 times. 10 to the 46 Jules for part. See, we have to find out the work and you took gravity. Now, gravitational forces acting downward. And the displacement is ah, on the horizontal axis. So the angle between them is 90 degrees. And we know that call sign knighted trees zero. So that means the worked on due to gravity when B is Europe. Thank you.

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