💬 👋 We’re always here. Join our Discord to connect with other students 24/7, any time, night or day.Join Here!

View Video Answer

Like

Report

$\cdot$ $\cdot$ $\cdot$ A 1.50 $\mathrm{kg}$ book is sliding along a rough horizontal sur-face. At point $A$ it is moving at $3.21 \mathrm{m} / \mathrm{s},$ and at point $B$ it hasslowed to 1.25 $\mathrm{m} / \mathrm{s}$ (a) How much work was done on the bookbetween $A$ and $B ?$ (b) If $-0.750 \mathrm{J}$ of work is done on the bookfrom $B$ to $C,$ how fast is it moving at point $C ?$ (c) How fastwould it be moving at $C$ if $+0.750 \mathrm{J}$ of work were done on itfrom $B$ to $C$ ?

(a) $W_{\mathrm{AB}}=6.06 \mathrm{J}$(b) $v_{3 \mathrm{C}}=0.75 \mathrm{ms}^{-1}$(c) $v_{3 \mathrm{C}}=1.6 \mathrm{ms}^{-1}$

Physics 101 Mechanics

Chapter 7

Work and Energ

Physics Basics

Applying Newton's Laws

Kinetic Energy

Potential Energy

Energy Conservation

University of Michigan - Ann Arbor

University of Washington

Hope College

Lectures

04:16

In mathematics, a proof is…

04:48

In mathematics, algebra is…

10:10

A 1.50-kg book is sliding …

03:45

A 5.00-kg package slides 1…

07:10

A 5.00 -kg package slides …

03:32

A 0.60$\cdot \mathrm{kg}$ …

02:57

In Fig. $7-33,$ a horizont…

03:25

A 350 -kg roller coaster s…

02:22

To push a 25.0 kg crate up…

08:33

You slide a box of books a…

04:17

A 0.60-kg book slides on a…

06:11

$\bullet$ $\bullet$ A 350 …

03:54

You place a book of mass 5…

01:49

A 0.60 -kg book slides on …

07:12

A crate of mass 10.0 $\mat…

06:53

A box of books weighing $3…

18:40

A 5.00-kg package slides 2…

0:00

A 25.0-kg box of textbooks…

06:02

A 15.0 -kg block is dragge…

04:28

An object of mass 3.00 $\m…

You push your physics book…

04:23

$\cdot$ You push your phys…

Okay, So from working ninja can ity Aah! War can kind of again is a theory. And we know that the blue net is equal to the final kinetic energy minus the initial kind Again, we're the kinetic energy is written as half and he's great and V is thie velocity and M is the mass of the body. And for I will just write the eye as in the initial velocity and for cave will drive fee f as in the final velocity. Now impart a Since the the objects lights from point A to point B, we can write the initial position I as a and the final position If, as b and we do so, r work candidate energy equation becomes the faltering, so we'll have a definite then we can take We can rate this equation as half empty a squared minus half and three b squared on Since we since m is common in both of these expressions So we take that outside and we have be a squared minus V c squared. We were given all the values for that. You can use them and solve for the network. For them we have 1.5 kg, then the is 1.25 meters per second. So we take square of that. The baby is 3.21 Meet over seconds squared are the whole thing is cleared. Then from there we take, we get the network as negative 6.5. See Jules Right now, One thing we should note here the negative sign corresponds to the decrease of kinetic energy. That means object is slowing down. That's why there's, ah, negatives and and if there's a positive sign, that means there's an increasing kind of the energy or the object is speeding up now in part B, we're again will be doing the same thing here. But here are your donation position is being on the final position is C. We are already given the, um W net or the total work done, which is negative. 0.75 Jules. So if we want to solve for K C, we'll have the fallen expression. Will have kids D plus w no. So all we're doing is since we assigned be toe I so we can take this guy on the left and we can take the unit on the right. So I left k f we can We can take a Iot on the left, so we'll have key f which is equal to K. I placed a unit. Andi, since cave is see So that's why we have Casey equals Katie first w net. From there, we can again use the same thing, which is half m v squared. So M is 1.5 kg. Then fee is 1.1 point 25 meters per second. Squared on the worked on double unit is negative. Sylar points having five jewels. From here we get Casey as class zero point for Toto. Jules. Now, as we mentioned that, K c Oops. Sorry about that. As I mentioned. That I can see is equal to huh? And he squared. So here will have the sea because we have subscript c in place of Qi. So from there we know that Casey is zero point for two jewels. And on the right side, we know that we have mass as 1.5 kg on dh. He sees the unknown that we need to figure out. And from there, if we take fi sea on one side and put the mask on the other side will have square root off twice off Casey, where cases plus 0.4 to 2 jewels. That's going to find four total Jules, divided by the mass, which is, um, one find five kg and we have a square root sign because we get rid of this square on the left. Right. And from there we get V C as 0.75 medium or second. Now in part, see, we'll do the similar thing. But instead ofthe negative w net being negative point point 75 we have now positive 750.7 fight Jules, as in as the network. So if we do the similar calculation, we get Casey as half off. 1.5 kg times 1.25 me never second holding a squared plus 0.75 jewels, which is 1.92 jewels. And the velocity will be 1.6 me never second. So you should go ahead and do the calculation by yourself. The cheque Will the results are true or not. So the only thing that's changing here is instead of a negative sign, we have a positive sign now. But the rest of the calculation is same as before. Thank you

View More Answers From This Book

Find Another Textbook

Numerade Educator

In mathematics, a proof is a sequence of statements given to explain how a c…

In mathematics, algebra is one of the broad parts of mathematics, together w…

A 1.50-kg book is sliding along a rough horizontal surface. At point A it is…

A 5.00-kg package slides 1.50 $\mathrm{m}$ down a long ramp that is inclined…

A 5.00 -kg package slides 1.50 $\mathrm{m}$ down a long ramp that is incline…

A 0.60$\cdot \mathrm{kg}$ book slides on a horizontal table. The kinetic fri…

In Fig. $7-33,$ a horizontal force $\vec{F}_{a}$ of magnitude 20.0 $\mathrm{…

A 350 -kg roller coaster starts from rest at point $A$ and slides down the f…

To push a 25.0 kg crate up a frictionless incline, angled at $25.0^{\circ}$ …

You slide a box of books at constant speed up a $30^{\circ}$ ramp, applying …

A 0.60-kg book slides on a horizontal table. The kinetic friction force on t…

$\bullet$ $\bullet$ A 350 kg roller coaster starts from rest at point $A$ an…

You place a book of mass 5.00 kg against a vertical wall. You apply a consta…

A 0.60 -kg book slides on a horizonal table. The kinetic friction force on t…

A crate of mass 10.0 $\mathrm{kg}$ is pulled up a rough incline with an init…

A box of books weighing $319 \mathrm{N}$ is shoved across the floor by a for…

A 5.00-kg package slides 2.80 m down a long ramp that is inclined at 24.0$^\…

A 25.0-kg box of textbooks rests on a loading ramp that makes an angle $\alp…

A 15.0 -kg block is dragged over a rough, horizontal sur- face by a 70.0 . N…

An object of mass 3.00 $\mathrm{kg}$ is subject to a force $F_{x}$ that vari…

You push your physics book 1.50 $\mathrm{m}$ along a horizontal table top wi…

$\cdot$ You push your physics book 1.50 $\mathrm{m}$ along a horizontalt…

06:33

Huygens probe on Titan. In January 2005 the Huygens probe landed on Saturn&#…

$\bullet$ Three moles of an ideal gas are in a rigid cubical box with sides …

04:18

$\bullet$ The gas inside a balloon will always have a pressure nearly equal …

04:04

A block of ice with a mass of 2.50 $\mathrm{kg}$ is moving on a fric-tio…

02:53

The The mass of the moon is about 1$/ 81$ the mass of the earth, its radius …

03:31

$\cdot$ A 40-year-old optometry patient focuses on a 6.50 -cm-tall photograp…

01:46

$\cdot$ A car is traveling at a speed of 63 $\mathrm{mi} / \mathrm{h}$ on a …

07:03

$\cdot$ $\cdot$ $\cdot$ A 1.50 $\mathrm{kg}$ book is sliding along a rough h…

05:48

$\cdot$ $\cdot$ A tow truck pulls a car 5.00 $\mathrm{km}$ along a horizonta…

03:22

$\bullet$ How many water molecules are there in a 1.00 $\mathrm{L}$ bottle o…