Question
$\cdot$ CE The radiation pressure exerted by beam of light 1 is half theradiation pressure of beam of light 2. If the rms electric field ofbeam 1 has the value $E_{0},$ what is the rms electric field in beam 2 ?
Step 1
So, we can write this as: \[P_1 = \frac{I_1}{c}\] \[P_2 = \frac{I_2}{c}\] where $P_1$ and $P_2$ are the radiation pressures of beam 1 and beam 2 respectively, and $I_1$ and $I_2$ are the intensities of beam 1 and beam 2 respectively. Show more…
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