00:01
All right, guys, let's take a look at the question.
00:03
Well, for the first question, we was asking us how much heat was required if we need to heat out the cold air from negative 20 degrees celsius to our body temperature, which is 37 degrees celsius.
00:16
Okay? so, while we know, the equation for the required heat is q equal to mc times delta t.
00:25
M is the mass.
00:26
C is the specific heat.
00:28
Dada t is the changing temperature.
00:30
Okay.
00:32
So we know initial temperature is negative 20 degrees celsius.
00:35
If we convert it to kelvin, it's 253 kelvin.
00:42
Okay.
00:45
And the final temperature is our human body temperature, which is 37 degrees celsius.
00:53
And we convert it to kelvin.
00:56
It's 310 kelvin.
01:00
Okay.
01:02
And so now we know the change temperature is, is equal to delta t which is t2 minus t1 which is 310 kelvin minus 153 kelvin which will give us 57 kelvin okay so that's the changing temperature in kelvin and also the specific heat for such air is given as well it was 1020 jou over kilogram times kelvin okay that's a specific heat for 1 liter error or 1 .3 grand error.
01:50
But in this case, we're talking about 0 .5 liter air in the process.
01:57
So the mass here is equal to 1 .3 grand, divided by 2, which is 0 .65 grand.
02:08
For the mass of the air, we need to raise the temperature from.
02:14
Okay, so now we have c, we have m, and we have delta t.
02:21
So q is equal to m, which is 0 .65 gram...