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$\cdot$ The cornea as a thin lens. Measurements on the cornea of aperson's eye reveal that the magnitude of the front surface radius of curvature is $7.80 \mathrm{mm},$ while the magnitude of the rear surface radius of curvature is 7.30 $\mathrm{mm}$ is 1.38 . If the cornea were simply a thin lens in air, what would be its focal length and its power in diopters? What type of lens would it be?

since the focal length is negative, the lens is $[$ diverging $]$

Physics 102 Electricity and Magnetism

Physics 103

Chapter 25

Optical Instruments

Electromagnetic Waves

Reflection and Refraction of Light

Cornell University

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Sheffield

Lectures

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all right, so the corneas thin lands here. And so we used the equation of the power of Finland's. The Finland's equation was served the one of a focal ing equals index of refraction of the lenses minus one times one of the radius of curvature one minus one of radio's coverage too. On dso Ah, these are but are wanting our tour, but positive because because our one is because I want the front surface is a con convex and so is our to the the rear surface from and so ah index of refraction is 1.38 and our one is 7.8 millimeters. Our two is seven point three millimeters. And so what we get is that focal ng f is negative 300 millimetres or negative 0.3 meters on DSO. Since F is negative, this is a diversion. Lives on DH, then Power and Diop Tres is to find as one over focal length in meters. So in this case it will be won over negative 0.3 meters. So power is negative. 3.23 Diop tres and that's it

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