00:01
According to conservation law of angular momentum, we know the initial angular momentum should be equal to the final momentum, which is l -i -e -qo -f here.
00:09
If we expanded, we have i -i -omegah -i -i -i -i is equal to i -f -o -megger -i -i is the initial moment of inertia.
00:19
And i -f is the final moment of inertia.
00:23
Omega -f is the final angular velocity.
00:27
If we do some arrangement here, we'll have the final angular velocity or another.
00:31
The final angular speed is equal to ii omega i .f.
00:37
So the initial moment of inertia should be equal to i0 plus 1 over 12 times m and n times r1 square.
00:44
I 0 is the moment inertia of the skater and then 1 half, i'm sorry, 1 over 12 m r1 square is the moment of inertia of the action that skater took first.
00:56
Okay? because initially the skater was prepared to speed like a slender rod, okay? and we know the moment of inertia of the slenderon is one half m r1 square.
01:08
If we plug in the values, we'll have ii is equal to 0 .4 kilogramtenths meter square, plus 1 of 12 times 8 kilogram, and then times 1 .8 meter to the power of 2...