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$\cdot$ Which of the objects shown in Figure 10.55 are in only translational equilibrium, only rotational equilibrium (about the axis $A$ , both translational and rotational equilibrium (about $A ),$ or neither equilibrium?

a)The body is only in rotational equilibrium because the torque acting equals zero.b)The body has both translational and rotational motion. Therefore, it has neither translational norrotational equilibrium.The body has rotational motion, so it is in translational equilibrium.The body is in translational equilibrium.The body is in both translational and rotational equilibrium.

Physics 101 Mechanics

Chapter 10

Dynamics of Rotational Motion

Newton's Laws of Motion

Rotation of Rigid Bodies

Equilibrium and Elasticity

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Winnipeg

McMaster University

Lectures

02:34

In physics, a rigid body i…

02:21

In physics, rotational dyn…

04:10

$\bullet$ (a) In each of t…

01:43

Conditions for Equilibrium…

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Is the object in figure 1…

00:24

A figure has $60^{\circ}$ …

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What are the necessary con…

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In Figure $\mathrm{P} 14.2…

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Give an example of an obje…

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Write the necessary condit…

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A figure has $50^{\circ}$ …

01:27

Write the necessary equati…

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Figure 11.22 shows a demon…

00:25

Consider the object shown …

00:32

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09:28

Two uniform rods, $A B$ an…

03:01

Show that $(0,0)$ and $(c …

02:25

Determine the torques abou…

01:31

If there is only one exter…

02:58

The system in Fig. $12-77$…

Hello Problem 35 asks us Which of these objects showing they give us five different objects is our end. Rotational equilibrium, translational equilibrium Both or neither Soto to kind of review here to be in translational translational equilibrium. You're net forces must be zero being rotational equilibrium. Your network must be zero, of course, to be in both. But these conditions must exist. Well, neither of these conditions will exist. So it's Look it bar, eh? About this rotation point, you can see that our net torques would be in equilibrium. They would be zero. But since we don't know the way to the bar, we can't tell if our net forces are zero. So for a this is rotational equilibrium on Lee Now for be. Since we moved the pivot point, our talks are no longer in equilibrium. They're no longer equal again. Same reasoning on we don't know the way to the bar. So we can't say our net forces are in equilibrium. So this is a neither here way. Concede that, um are net forces would be an equilibrium that they would be equal doesn't have a downward force in an upward force. But we can see that both of these provide a clockwise torque, so it would be rotating. So our talks are not, um, equal. So this is translational on Lee here. We can see that Arnett forces balance 10 up in a total of 10 day on. So we've got translational. But we would see that the network is clockwise motion about this pivot point, and so are it will not be in rotational equilibrium. And finally, with this picture up just a little bit. Here we look at this last one. Now we can see that Arnett forces balance out. We have a 40 this direction. 40 this direction they are parallel to each other are and so are we would be in translational equilibrium. Now, what about our torques? Well, since both of these go through the pivot point, we have no talks at all. So we are in rotational equilibrium. So we would actually be in this

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