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$\cdot$ You are given a sample of metal and asked to determine its specific heat. You weigh the sample and find that its weight is 28.4 $\mathrm{N}$ . You carefully add $1.25 \times 10^{4} \mathrm{J}$ of heat energy to the sample and find that its temperature rises 18.0 $\mathrm{C}^{\circ} .$ What is the sample's specific heat?

$C=240 \mathrm{J} / \mathrm{kg} . \mathrm{K}$

Physics 101 Mechanics

Chapter 14

Temperature and Heat

Thermal Properties of Matter

The First Law of Thermodynamics

Cornell University

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

Lectures

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Let'S, let's take a look at the question? Okay, so the question was asking us to determine for such things. While we know the heat required was 1.25 times 10 to the power 4 and the change in temperature is 18 degrees celsius, and we know the force is 28.4 newtons. So we can know the mass is just simply equal to force over gravitational constant, because here what i'm talking about the gravity? Okay, so now we know it's q to m tenesco, simply equal to q over m times delta t and s f g. So i know why block the g here, let me rewrite it so f over g, you know what i mean do is so it's q over f over g times, tokay and we know q was just plug in q, which is 1.25 times 10 to the power 4, over f o g, which is 28.4 newtons over 9.8 meter per second square and delta t was just 18 degrees celsius, which will give us about 240 joules per kilo gram times, kelvin, okay and sluts the facility for this question. Thank you.

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