cdots-as-a-train-accelerates-away-from-a-station-it-reaches-a-speed-of-47-mathrmm-mathrms-in-50-math

Question

\cdots As a train accelerates away from a station, it reaches a speed of
4.7 $\mathrm{m} / \mathrm{s}$ in 5.0 $\mathrm{s}$ s. If the train's acceleration remains constant, what
is its speed after an additional 5.0 s has elapsed?

Nathan Silvano · Accepted Answer

So we know that this in this problem we have a train that start to deserve aerators away from the station and reaches a velocity off. Let&#x27;s see velocity for 0.7 meters per second and he reaches this velocity in just five seconds. We want to know if the villa&#x27;s if the acceleration of the train remain constant. What&#x27;s going to be his velocity after more five seconds? What is going to be his velocity in a toto time since the beginning of the movement off 10 seconds. This is the total time since the beginning off the movement. Okay, well, we know that there is a creation that relates velocity off. Time is this is a question describes the velocity of the train in each single time. Immigration is equals 30 plus eight times T, while the initial velocity is zero cause his arrest. So we just need to know the acceleration and we can sort of problem. Let&#x27;s see the first part. We know that he reaches a velocity off 4.7. This is equal the acceleration. We don&#x27;t know times five seconds. So exhilaration is just for 0.7 4.7 divided by five That sequel. True. 0.94 meters per second squared. Okay, so we have deceleration. L We just need to use function to describes the philosophy of the train in any instant of time. Zero Again zero. We just want to know the velocity of the train. 10 seconds. So 0.94 It&#x27;s too many of points in here times thin sections. So the final velocity off the train is just nine point for meters per second. That&#x27;s the final answer. Thanks for watching.

Joshua Bell · Answer

Hello and Good, dave. We&#x27;ve got a physics problem about a train going up a hill. So when we start with the diagram, there&#x27;s a steep hill for you, here&#x27;s my train, physicists train, you know, moving up the hill at some speed v it&#x27;s fixed at some point the car breaks off of the train and become separated. Now, initially it&#x27;s moving at the same speed as the as the train, but it heads up with some final speed that&#x27;s not given, all we&#x27;re told is that It takes five seconds to get 30 m behind the rest of the train. So Groups 55 2015. So the wrong way to do this will make things very difficult if you try going to your formula sheet and pulling out mathematics formulas and you try use, say, for example, this guy that is going to get you absolutely nowhere because we don&#x27;t know either of these velocities, neither of these is unknown. We cannot use this formula. The easy way to do this problem actually involves a slightly different way of looking at the problem altogether. Let&#x27;s imagine that we are actually standing on this train and we are working within our own reference frame. So to us, this train is standing still From our point of view. So this is zero m/s, we&#x27;ll be right that high on the screen. But the idea is that it&#x27;s initially it looks like it&#x27;s at rest to us. So in this case, if we were to try to say, oh, I don&#x27;t know, maybe use this formula, This might get us somewhere because now we&#x27;re able to throw away this velocity, we don&#x27;t know because we said It&#x27;s equal to zero from our point of view, The acceleration is going to be the same from either point of view, whether you&#x27;re standing still on the ground or standing on the train, the good news is from this point of view. Now, this whole term goes away And so now we just have 30 equals one half times the acceleration we want times the time, which is five seconds Squared gives us 25 and it looks an awful lot like the acceleration is just equal to 60 over 25. And so with the proper analysis of the situation, that&#x27;s all it takes, the acceleration is 60/25 m/s squared. You can reduce that if you want to, um, you can leave it like that, you can turn it into a Destiny or whatever the case, it&#x27;s a little bit more than two. That&#x27;s all you need, folks have a good one

Justin Hameline · Answer

a problem. 23 of Chapter two states Starting from rest a subway train first accelerates to 25 meters per second, then breaks 48 seconds after starting. It&#x27;s moving at 17 meters per second. What&#x27;s its average acceleration in this 48 2nd interval? What I began by doing was right out the given information which is our initial velocity, our time and our final velocity using the Kinnah Matic equation Final velocity is equal to initial velocity plus acceleration times time We will be able to solve this problem What we first want to dio is solve or our acceleration. To do this, we first need to move our initial velocity to the opposite side. Therefore VF minus of V I is equal to 80 and then both divide both sides by t Thus we have VF minus V. I divided by t is equal to our acceleration. Now all of this information we already have Therefore we have 17 meters per second minus 25 meters per second divided by 48 seconds gives us the value negative 0.167 meters per second squared has our acceleration Now this makes sense because the train

Zulfiqar Ali · Answer

but it won&#x27;t be. Speed can be determined by using The square. B is equal to these were a les two times. Stand into Lex relation into position of B minus. Position off a and now let&#x27;s plugging numbers 30 square minus to motive. Live eyes in 0.25 Multiply by 412 minus zero, So ah, speed it point. Be easy book to 26.34 leader per second. We&#x27;ll find normal X relation. We have to calculate Proteas occur. We have ity by divided by t X is equal to 0.2 times e to the power X divided by 1000. Also a d screen. Why Divided by D. X square is 0.2 motive lie by 10 to the power minus three multiplied by he to the power extra body by 1000. Right now we know date readies off curve is equal to one place de by divided by the ex Whole square to the power three divided by do divided by d squared Why divided by D X square Now we substitute Divi divided by the axe and the square right by D X squared Therefore radius is equal to one. Lists 0.2 times E to the power X, divided by 1000 Ah, whole square to the power three, divided by two, divided by 0.2 Most of my bite into the power minus three. Motive. My body to the power X, divided by 1000 right and sold radius when X is equal to 400 is equal do 3808.96 m. Now let&#x27;s find out Normal X relation. Normal X relation is equal to the square divided by role. 26.34 Screener divided by role, which is 3808 0.96 So normal X relation is equal to 0.1 h, 22 m where second square and further. Let&#x27;s find out Total X relation. Right, so total X relation is able to root tangents and ex relations square less normal X Relations were so we have route zero point five square lists a 0.18 to 2 square, so total exhilaration is equal to 0.3 09 m per second square. Right, so this is Cedar Point trades you, don&#x27;t I? Ah, meter per second square. It&#x27;s 96 rage

Kara Merfeld · Answer

right. So, amigo, acceleration is basically how fast something speed changes. So the equation for that is acceleration is the change in velocity over a change in time. And basically, we just have to plug in the things that we know. So this is Ah, the ending velocity or the velocity of time too minus starting velocity or the velocity of time. One divided by how much time that takes. So he said it was 50 a za smiles or kilometers kilometers 50 um, kilometers per hour. 00 Um oh, uh, minus 40 kilometers per hour. It happens in 10 seconds. Okay, so basically, we have 50 minus forties, 10 kilometers per hour per 10 seconds. Sophie, subtract all that out. We have our first RV. It&#x27;s attract 44 50 in the dry, but 10 we&#x27;re left with one kilometer Kurt per hour per second. If we were to put this in more standard units, we could do some dimensional. Alice is to put this in either kilometers per hour squared or kilometers per second squared. Oh, and I guess we should probably do that. So in order to do that. So this this here what? We have is a perfectly correct answer, but we could make it more conventional by changing some units around. So we can either change the seconds in powers or the hours into seconds. And when we do, that is say, okay, we multiply it by, um, Roy, I totally didn&#x27;t mean to make that line right there. We can multiply it by, um, the fact that every hour has 3000 600 seconds per one. Our what we&#x27;re doing, we multiply this number, we can do that. And the reason we can do that is because 3600 seconds is equal to one hour. So we&#x27;re really just multiplying by one. And then we have here. You have a cancellation. You can see that this seconds on top. Cancel It cancels with this seconds on bottom, and we can multiply that out. And this is then, um, 36 100 uh, kilometers per hour per hour. Work per hour. No. Started me to write that. Cross you there or per hour. Squirt

Zulfiqar Ali · Answer

because we have initial been lost nation lost you, Xena and one is equal to 0.5 meters per second squared well de want is equal to 62nd and, uh, two is equal to 902nd and a two physical too minus one meter per second squared on a final velocity is equal to zero. Well, first we need to determine distance traveled up for a spot of Johnny and final speed of Dick Johnny. So let us find out this one or this one is equal to a one times rt one square divided by to let&#x27;s plug in numbers. Is it a 0.5 times 60 square? Divide by two, which is equal to 900 meter on to be one is equal to a one times the one on C 2.5 times 16. So we want is equal to hurting me to per second. Okay. And so after first part of the journey, the train traveled 900 meters and its philosophy lost 30 meters per second. Now, in the second part, it is moving with a constant velocity which is equal paternity to per second for 15 minutes, so distance traveled in this part is a steward, which is equal to we won times t two on that is 30 multiplied by nine and Greta, which is equal to 27 on house age meter. Okay, now, after this part, the train started decelerating until it stopped so distant distance traveled. Did bring this party&#x27;s, uh, using the F square is equal to Ah, we once were less 28 times as three zero is equal to 30 square. I knew stew. Want a BlackBerry? One month of my buys. Three solving for in distance traveled s three is equal to 450 meter and total distance traveled. Use It&#x27;s one place. Yes. Stupid Lis s three. Nine in grade. Let&#x27;s 27 1000 plus 450 which is equal to 28,000 315 meter

Problem

A particle has an acceleration of $+6.24 \mathrm{…

Problem 38 Easy Difficulty

\cdots As a train accelerates away from a station, it reaches a speed of
4.7 $\mathrm{m} / \mathrm{s}$ in 5.0 $\mathrm{s}$ s. If the train's acceleration remains constant, what
is its speed after an additional 5.0 s has elapsed?

Answer

velocity $v_{f}$ after 5 seconds of constant acceleration is 9.4 $\mathrm{m} / \mathrm{s}$

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velocity $v_{f}$ after 5 seconds of constant acceleration is 9.4 $\mathrm{m} / \mathrm{s}$

Physics

Elyse G.

Marshall S.

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Math Review - Intro

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James S. WalkerPhysics

Elyse G.

Marshall S.

Farnaz M.

Aspen F.

James S. Walker

Physics