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\cdots As a train accelerates away from a station, it reaches a speed of4.7 $\mathrm{m} / \mathrm{s}$ in 5.0 $\mathrm{s}$ s. If the train's acceleration remains constant, whatis its speed after an additional 5.0 s has elapsed?

velocity $v_{f}$ after 5 seconds of constant acceleration is 9.4 $\mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 2

One-Dimensional Kinematics

Motion Along a Straight Line

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So we know that this in this problem we have a train that start to deserve aerators away from the station and reaches a velocity off. Let's see velocity for 0.7 meters per second and he reaches this velocity in just five seconds. We want to know if the villa's if the acceleration of the train remain constant. What's going to be his velocity after more five seconds? What is going to be his velocity in a toto time since the beginning of the movement off 10 seconds. This is the total time since the beginning off the movement. Okay, well, we know that there is a creation that relates velocity off. Time is this is a question describes the velocity of the train in each single time. Immigration is equals 30 plus eight times T, while the initial velocity is zero cause his arrest. So we just need to know the acceleration and we can sort of problem. Let's see the first part. We know that he reaches a velocity off 4.7. This is equal the acceleration. We don't know times five seconds. So exhilaration is just for 0.7 4.7 divided by five That sequel. True. 0.94 meters per second squared. Okay, so we have deceleration. L We just need to use function to describes the philosophy of the train in any instant of time. Zero Again zero. We just want to know the velocity of the train. 10 seconds. So 0.94 It's too many of points in here times thin sections. So the final velocity off the train is just nine point for meters per second. That's the final answer. Thanks for watching.

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