ce-suppose-you-perform-an-experiment-on-the-photoelectric-effect-using-light-with-a-frequency-high-e

Question

CE Suppose you perform an experiment on the photoelectric effect using light with a frequency high enough to eject electrons.
If the intensity of the light is increased while the frequency is held
constant, describe whether the following quantities increase, decrease, or stay the same: (a) The maximum kinetic energy of an
ejected electron; (b) the minimum de Broglie wavelength of an
electron; (c) the number of electrons ejected per second; (d) the
electric current in the phototube.

Zulfiqar Ali · Accepted Answer

part, eh? A maximum. Ah, kinetic energy Often rejected Electron remains the same. Maximum kinetic energy or and ejected electron remains the same. Remains the same art be, uh, the minimum de broccoli. Bad land off in electron also demands the same. So the minimum the minimum, not de Brantley Fab Lind, Often electron. Um oh, and electron remains the same. Remains the same. Artsy, the number of rejected the number of electrons ejected per second in crazies. But the number the number Oh, electrons ejected 1st 2nd burger. Second increases in crazies and body on the electric current I in the photo tube, uh, increases increases.

Zulfiqar Ali · Answer

part, eh? The maximum kinetic energy often oh, family rejected electron increases. Uh, the maximum, uh, kinetic energy. Often electron, often electron increases part B The minimum the broccoli that land lender open electron did crazies, Dick raises, and Marcie the number of electrons ejected per second. So number off electrons ejected per second or second decreases did crazies. Finally, body electric around in the photo to you also decreed it. So I electrical and in the 4 to 2 wanted to you. To you It&#x27;s to you Dick raises.

Jayashree Behera · Answer

So once the special frequency is reached, the current begins to flow. The current now cannot increase with increasing frequency, although the frequency will help in starting the current flow. But after that, once the current flu has started, an increase in frequency will no longer longer cause an increase in correct. And now to increase the current, the intensity off light has to be increased on increasing the density off light increases the number of photons and this would cause more electrons to be educated. So the correct option is option. Eat. Thank you.

Zulfiqar Ali · Answer

art, eh? Huh? Part in development Off the light should be decreased in order to cause electrons to be rejected on the battle end off the light lander. Javelin. Uh, off the light off the light, uh, should be decreased. Should be ah, decreased should be decreased in order to cause electrons to be ejected. Uh, we know that e is equal to edge and, uh, see is equal lender, and it cools. See, divided by r f equals C divided by lambda and substituting f We have, ah, e equals or edge of equals Each times see divided by lender. So it&#x27;s obvious from this equation. If lambda is decreased, then the energy off for dawn increases. And then it can, uh, because electrons to be ejected from the metal surface. Uh, no legs sold. Part B. Well, in Barbie, the second option is the best explanation. Ah, the energy off for dawn is proportional to its frequency. Are these radically proportional to a frequency and that is inversely proportional to its valent. And, uh, energy is inversely proportional to, uh, babbling to increase the energy off the photons. Um, so they can eject electron one must decrease. Ah, Valent. One must decrease the, uh, prevalent. So second option is the best explanation

William Mills · Answer

His question begins with the description it says the outermost electron oven. Adam has a binding energy of 2.5 electron volts that says the Adam is exposed to light of a high enough frequency to cause exactly one electron to be ejected. And the eject electrodes found have a kinetic energy of two points. Your electron volts I ran here the binding energy 2.5 connect candy deep 10 This question asks if the intensity of light were to be decreased. That is, that the light is made dimmer. How would it affect the kinetic energy of the ejected Elektrim? And, um, it&#x27;s important to know that when you say that the intensity applied decreased, where they gets dimmer, that is completely independent of what the wave length and frequency of that light are. Those stayed the same regardless of the intensity of the light or the brightness of the light. And so if changing intensity does not change wavelength or frequency, it would have no change on the energy of that photons of light. Therefore, if the energy of the photon light isn&#x27;t changing, the energy that you apply to that electron also doesn&#x27;t change so it would still have two points your electron volts of kinetic energy after it&#x27;s been ejected. And that&#x27;s described to us by Option D. Decreased intensity would have no effect on the Conn JD Electron because intensity has nothing to do with wavelength or frequency. The answer is D.

William Mills · Answer

this question begins with the description. It says the outermost electron of an atom has a binding energy of 2.5 electron volts. Then the atom is exposed to light of a high enough frequency to cause exactly one electron to be ejected. And the ejected electron has a kinetic energy of two points here. Electron volts. Ever hear the binding energy? 2.5 can&#x27;t nd 2.0. This question asks. If the wavelength of light is to be shortened. How would it affect the kinetic energy of the ejected electron? And so all of the energy in this system, what it takes to kick the electron out 2.5 electron volts and what energy that electron has once it leaves 2.0 electron volts all comes from the photons. And so it tells us, if we shorten the wavelength, what happens to the energy of the photon that&#x27;s admitted here? First, look at what the relationship is between wavelength and energy, so we decrease the wavelength given to us by land to hear we&#x27;re increasing the frequency of that radiation because speed of light is a constant. And then in this equation, if we increase the frequency. We also increase the energy because paper blanks constant, it&#x27;s constant here. And so decreasing wavelength would increase the energy of the photo. That means that we still need 2.5 electron volts to kick that electron out. But because the energy is greater, we have more energy to give to the electron to be converted into its kinetic energy. So because that photo will provide much more energy than the 2.5 needed to kick the electron out, it would have more kinetic energy left over. And that is described to us by option beat. Ah, shorter wavelength would, um I&#x27;m sorry by a A short wavelength would increase the kinetic energy that option a

Problem

CE Suppose you perform an experiment on the photo…

Problem 80 Hard Difficulty

Answer

a) The maximum kinetic energy stays the same
b) The minimum de Broglie wavelength of an electron stays the same.
c) The number of electrons ejected per second increases.
d) The electric current in the photo tube increases.

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a) The maximum kinetic energy stays the sameb) The minimum de Broglie wavelength of an electron stays the same.c) The number of electrons ejected per second increases.d) The electric current in the photo tube increases.

Physics

Marshall S.

Farnaz M.

Aspen F.

Jared E.

Wave Optics - Intro

Multiple Aperture Interference - Overview

James S. WalkerPhysics

Marshall S.

Farnaz M.

Aspen F.

Jared E.

a) The maximum kinetic energy stays the same
b) The minimum de Broglie wavelength of an electron stays the same.
c) The number of electrons ejected per second increases.
d) The electric current in the photo tube increases.

James S. Walker

Physics