Question
Chain Rule Suppose that $f(x)=x^{2}$ and $g(x)=|x| .$ Then the compositions$$(f \circ g)(x)=|x|^{2}=x^{2} \quad \text { and } \quad(g \circ f)(x)=\left|x^{2}\right|=x^{2}$$are both differentiable at $x=0$ even though $g$ itself is not differentiable at $x=0 .$ Does this contradict the Chain Rule? Explain.
Step 1
In this case, we have $f(u) = u^2$ and $u(x) = |x|$. According to the chain rule, the derivative of $f \circ g$ is given by $\frac{df}{dx} = \frac{df}{du} \cdot \frac{du}{dx}$. Show more…
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Chain Rule Suppose that $f(x)=x^{2}$ and $g(x)=|x| .$ Then the composites (f \circ g)(x)=|x|^{2}=x^{2} \quad and \quad(g \circ f)(x)=\left|x^{2}\right|=x^{2} are both differentiable at $x=0$ even though $g$ itself is not differentiable at $x=0 .$ Does this contradict the Chain Rule? Explain.
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