00:01
In this question, we want to find a vector that is normal to the surface, x squared plus y squared minus z equals zero, at the point 3, 4, 25.
00:09
Then i'm going to find the equations of the tangent plane and the normal line to the surface at that point.
00:16
So here i have a surface that is of the form f of x, y, z equals some constant k.
00:25
And so in order to get my normal vector, i need the gradient of f.
00:30
So the gradient of f consists of the partial of f with respect to x, 2x, the partial with respect to y, 2y, and the partial with respect to z, negative 1.
00:43
Now i need to evaluate my gradient vector at the point i was given, 3, 4, 25.
00:50
When i do, i get 6, 8, negative 1, and that is my normal vector.
00:58
So that was the first part of this question.
01:00
Now, i want the tangent plane.
01:06
So to write the equation of a tangent plane, i need a normal vector, which i now have, and a point, which i have as well.
01:14
So i take the x component of the normal vector, 6, times the quantity of x minus the x coordinate, 6 times the quantity of x minus 3, plus the y component of my normal vector, 8, times the quantity of y minus 4.
01:32
And then it's minus, minus 1, times the quantity of z minus 25.
01:39
All of this equals 0.
01:41
That would be my tangent plane...