00:01
Hi, in the given problem, charge over the particle is q is equal to minus 2 .0 into 10 to power minus 9 cullum and electrostatic force acting on it that is given as f is equal to 3 .0 into 10 dash to the power minus 6 newton and that is downward in direction.
00:51
So in the first part of the problem using the expression for electrostatic force f is equal to product of the charge with the electric field.
01:02
We get an expression for electric field as f by q.
01:08
Here it will be for force this is 3 .0 into 10 dash per minus 6 newton divided by charge which is 2.
01:18
In magnitude the charge is 2 .0 into 10 minus 9 cullum.
01:24
So finally magnitude of this electric field here comes out to be 1 .5 into 10 dash to 3 newton per culum which is the answer for the first part of this problem.
01:40
And this electric field should be directed upward because the charge is negative and it is experiencing a force in downward direction and electric field is always from positive to negative so this negative charge should experience a force towards the positivity of electric field means in a direction opposite to the electric field so this should be upward electric field should be upward now in the second part of the problem, 4 proton which is kept in the same electric field, the charge carried by a proton is equal to 1 .6 into 10 dash per minus 19 kulam.
02:27
So the force experienced by this proton f p will be the product of e, the charge carried by electron or sorry proton.
02:39
With the electric field...