00:01
Given our function is fx equals root over of x, we can substitute or we can let fx as y.
00:11
So we get this equation.
00:13
Now squaring both side, our equation will become y square equals x.
00:17
Now name this as equation number one.
00:19
Now firstly we will check symmetry with respect to x -axis, that is, symmetric of, symmetry of this function, symmetry of the graph of this function with respect to, firstly we'll check with respect to x -axis.
00:35
So to check symmetry with respect to x -axis, we will replace y with minus y in equation number 1.
00:42
So we get minus of y whole square equals x, which becomes y -square whole square, y -square equals to x.
00:50
So this is same as the original equation equation number 1.
00:53
So we can say that yes, our graph is symmetric with respect to y -axis.
00:58
Now to check symmetry with respect to, the graph is symmetric with respect to x -axis...