00:01
We have to determine the configurations at the asymmetric centers of this compound.
00:05
So i've reached around the compound and we have asymmetric center here and one here, since both of these carbons are attached to four unique groups.
00:15
So if you look at this carbon on the left, we can rank its groups in order of priority to determine its configuration.
00:22
So oh will have the highest priority since oxygen has the highest atomic number out of carbon, the carbon and the hydrogen.
00:30
Now this is bonded to these two groups here that start with a carbon.
00:35
So until then, they have equal priority, but then we have to look at what those carbons are bonded to.
00:40
So this carbon here is bonded to a nitrogen and a carbon and a hydrogen.
00:46
And this carbon here on the left is bonded to a carbon and a hydrogen.
00:52
Or a carbon, sorry, this carbon here is bonded to two carbons and a hydrogen.
00:59
So we've compared this, carbon with this carbon.
01:02
The carbon here will have a higher priority since it's bonded to that nitrogen, and nitrogen has a higher atomic number than carbon.
01:11
So this group will have priority two.
01:15
This group will have priority three, and hydrogen has the lowest priority.
01:19
So if we draw arrows from 1 to 2 and 2 to 3, they go in a clockwise direction...