We have 1 chlorine atom on the left side of the equation and 2 on the right side. To balance this, we need to put a coefficient of 2 in front of NaCl. Now, the equation becomes:
\[2\mathrm{NaCl}(a q)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{MnO}_{2}(s)
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