00:01
Okay, so for this question, for part a, they want us to calculate the entropy of the reaction.
00:07
So the delta h of a reaction is equal to the sum of the delta h on the product side, minus the sum of the delta h on the reacting side.
00:23
Right, so let's look up, we can look up the delta h of all of these in appendix l.
00:29
So delta h of reaction, let's start with the product side.
00:33
So we have ch3, ch3 cl, right? so we have one mole of ch3cl times it by.
00:44
If we look at appendix l, we see it's negative 8 .63 .68 kilojoules per mole, right? but we also have hcl as another product.
00:57
So we can write one times by, let's look at the value for hcl, and we should get negative 92 .31 kilojoules per mole.
01:05
Now that's all of the products.
01:08
Now let's look at the react inside.
01:11
So we have ch4, right? so we have one mole of ch4.
01:14
Let's multiply that by the delta h, which is negative 74 .87 kilojoules per mole.
01:23
Plus, we have two moles of cl, and we see that co gas is 121.
01:33
Oops, it's 121 .3 kilojoules per mole...