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Choose the correct method from Sections 6.1, 6.2, or 6.3 to factor each of the following.$$12 x^{3} y^{3}-18 x^{2} y^{3}+15 x^{2} y^{2}$$

$3 x^{2} y^{2}(4 x y-6 y+5)$

Algebra

Chapter 6

Factoring and Quadratic Equations

Section 3

Factoring Trinomials of the Form $a x^{2}+b x+c 454$

Equations and Inequalities

Quadratic Functions

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Okay, So where s the fact that our fallen So it's that factoring out a common factor of three as well as an X squared and a Y squared. So we're left with 12 divided by three, which is for we took to excel. So we have one remaining too wise to wear water. Meaning? Okay. And then we have negative 18 divided by three. I give this thing to six. We took two out to exit out. So there's no remaining and two wise. So we have one. Why remaining? And now 15 divided by three. That gives me fine. And then we have Let's see, two exes out and two wives out. So we have four X. Why minus six. Wife was fired.

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