Question
Choose the statement that is not true. Assume $b \neq 0, c \neq 0$ and $d \neq 0$ as necessary.(a) $\frac{a c}{b c}=\frac{a}{b}$(b) $\frac{a}{b}+\frac{c}{b}=\frac{a+c}{b}$(c) $\frac{a}{b}-\frac{c}{d}=\frac{a d-b c}{b d}$(d) $\frac{\frac{d}{b}}{c}=\frac{a c}{b d}$
Step 1
We have $\frac{a c}{b c}$. Since $c \neq 0$, we can cancel out $c$ from the numerator and the denominator. This gives us $\frac{a}{b}$, which is exactly what option (a) states. So, option (a) is true. Show more…
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Choose the statement that is not true. Assume $b \neq 0, c \neq 0$, and $d \neq 0$ as necessary. $$ \text { (a) } \frac{a c}{b c}=\frac{a}{b} \quad \text { (b) } \frac{a}{b}+\frac{c}{b}=\frac{a+c}{b} $$ $$ \text { (c) } \frac{a}{b}-\frac{c}{d}=\frac{a d-b c}{b d} \quad \text { (d) } \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a c}{b d} $$
Review
Rational Expressions
Multiple Choice Choose the statement that is not true. Assume $b \neq 0, c \neq 0,$ and $d \neq 0$ as necessary. (a) $\frac{a c}{b c}=\frac{a}{b}$ (b) $\frac{a}{b}+\frac{c}{b}=\frac{a+c}{b}$ (c) $\frac{a}{b}-\frac{c}{d}=\frac{a d-b c}{b d}$ (d) $\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a c}{b d}$
Reasoning Consider that $\frac{a}{b} \div \frac{c}{d}=\frac{a}{b} \cdot \frac{d}{c}$. Why must it be true that $b \neq 0, c \neq 0,$ and $d \neq 0 ?$
Rational Expressions and Functions
Multiplying and Dividing Rational Expressions
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