00:01
Okay, this problem takes us into some geometry.
00:06
So what's really important here is that this incident ray and the reflection ray are traveling at the same speed.
00:14
So they cover the same amount of distance and a set amount of time.
00:18
So take this point, oops, use a pen here, take this point on our ray and know that this amount of distance.
00:34
Since traveled would be equal on the other side because it's going at the same speed.
00:39
It's in the same medium, and this creates an isosceles triangle.
00:46
So if we have an isosceles triangle where the base of the triangle is parallel to the surface of the mirror, that would mean that the normal line is a perfect bisector of this triangle.
01:01
If this is the perfect bisector, it creates two triangles with congruent angles.
01:11
So this angle would be equal to this angle.
01:17
So your angle of incidence and angle of reflection are equal...