00:01
Okay, if you wanted to integrate this, if you integrated the left -hand side, d -y -d -x, that's going to end up giving you just your y equation.
00:10
And on the right, i would definitely rewrite this.
00:13
So the radical, if you move the radical up to the numerator, it would be to the negative one -half power.
00:20
A square root is the same as the one -half power.
00:23
Since it was in the denominator, you make it negative one -half.
00:25
And then you can move the x over here on the...
00:32
That side.
00:34
And you can do that because this fraction is the same as x over one times one over the square root.
00:43
Okay, so i again move the square root up and just move the x to the back.
00:48
So then i'm going to multiply both sides by dx so i can just see, get the integration of dy by itself on that side.
00:57
And then i put dx back here.
01:02
Okay, so this is a u -s substitution type of you will be the item raised to the power.
01:09
Your du then would be 2x dx.
01:17
So we're going to rewrite this integration as u to the negative 1 half.
01:21
And then anything left over in the problem has to match up with the du...