00:01
Christian is making an entirely interverse as shown in figure 435.
00:04
That is, he traverses a chasm by stringing a rope between a tree and one side of the chasm in a tree on the opposite side, 25 meters away.
00:14
The rope must act sufficiently so won't break.
00:16
Assume the rope can provide attention force up to 29kn before breaking and use the safety factor of 10.
00:33
That is, the rope should only be required to undergo a tension force of 2 .9kn.
00:37
At the center of the tireline traverse, this should happen.
00:41
Okay, so for a, we want to determine the distance x at the rope and a sag if it is to be within its recommended safety range in christian's mass is 72 kilo kilograms.
00:52
So here's what we know.
00:54
We know the distance is 25 meters.
00:57
We know that we can undergo up to 29kn.
01:11
We know that the tension force is 2 .9 and the mass is 72 kilograms.
01:30
So we're looking for distance x at the rope must sag.
01:36
We want a quick visual here.
01:40
Then we've got our tension force vectors and we've got theta, the angle.
02:00
We're going to have our gravity.
02:04
Gravity and we've got our distance of 25 and we want to find x.
02:18
One way to find x is by using theta.
02:24
We could say that the tangent of theta is equal to opposite over adjacent and so the opposite could be the value of x over the adjacent which would be 25 over 2.
02:52
We just need to find theta.
02:59
There are two forces acting on this man...