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Problem 71 Easy Difficulty

Chromium(III) oxide reacts with hydrogen sulfide (H2S) gas to form chromium(III) sulfide and water:
\mathrm{Cr}_{2} \mathrm{O}_{3}(s)+3 \mathrm{H}_{2} \mathrm{S}(g) \longrightarrow \mathrm{Cr}_{2} \mathrm{S}_{3}(s)+3 \mathrm{H}_{2} \mathrm{O}(l)
To produce 421 $\mathrm{g}$ of $\mathrm{Cr}_{2} \mathrm{S}_{3},$ how many (a) moles of $\mathrm{Cr}_{2} \mathrm{O}_{3}$ and (b) grams of $\mathrm{Cr}_{2} \mathrm{O}_{3}$ are required?


$\mathrm{n}\left(\mathrm{Cr}_{2} \mathrm{O}_{3}\right)=2,1 \mathrm{mol}$
$\mathrm{m}=\mathrm{n}^{*} \mathrm{Mr}=2,1^{*} 152=319,2 \mathrm{g}$


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