Question
Circum circle of an equilateral triangle $\mathrm{ABC}$ is $\mathrm{x}^{2}+\mathrm{y}^{2}+2 \mathrm{gx}+2 \mathrm{fy}=0$. Then its incircle is(a) $x^{2}+y^{2}+2 g x+2 f y=0$(b) $4\left(x^{2}+y^{2}\right)+8 g x+8 f y+3 g^{2}+3 f^{2}=0$(c) $x^{2}+y^{2}+8 g x+8 f y+3 g^{2}+3 f^{2}=0$(d) $x^{2}+y^{2}+2 g x+2 f y+3 g^{2}+3 f^{2}=0$
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In an equilateral triangle, the circumcenter coincides with the incenter, but the radii are different. Show more…
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VECTOR ANALYSIS
The curl and Stokes' theorem
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