00:01
We're using a 5 % significance level to find out whether the mean for day shift production is equal to the afternoon shift or whether the afternoon shift actually produces more than the day shift.
00:19
And our data is we have our, this is for our day, and we have that that mean, oops, x bar, the x bar for the day, is 345 units.
00:36
The standard deviation for the day is 21 units and the sample size is 54.
00:44
For the afternoon, we have the mean being 351, so looks higher.
00:52
The question is, is it significantly higher? look at these standard deviations.
00:56
We do have quite a bit of variability and our sample size is 60.
01:00
Now, we also notice that both these sample sizes are greater than a equal to 30.
01:05
Therefore, your textbook allows us to use a z value to estimate the test statistic.
01:11
So when we go through and find our little critical value, we're finding a critical z value, and we want to have all 5 % in the lower tail because of us doing a one -tail test with less than.
01:25
And so this z value will be negative.
01:27
And the area that has 5 % in that lower tail is a negative of 1 .645.
01:37
And this is where we will reject our null...