classify-these-reactions-as-combination-decomposition-single-exchange-or-double-exchange-copy-the--2

Question

Classify these reactions as combination, decomposition, single exchange, or double exchange. Copy the equations, fill in any missing products, and write a balanced equation for each reaction.
a. $\mathrm{NaOH}(a q)+\mathrm{HNO}_{3}(a q) \longrightarrow \operatorname{NaNO}_{3}(a q)+$ ________ $(l)$
b. $C_{2} \mathrm{H}_{4}(g)+\mathrm{Cl}_{2}(g) \longrightarrow$ ________ $(g)$
c. $\mathrm{Cl}_{2}(g)+\mathrm{MgBr}_{2}(s) \longrightarrow \mathrm{Br}_{2}(s)+$  ________ $(s)$

Vishal Sharma · Accepted Answer

in problem three classified these reactions as a combinations the composition, single exchange or double exchange and also find out the missing product in these reaction and balance the equations. So this question is taken from the topic types off reaction and based on the reaction, we can identify which type of reaction can take place. So this is the first reaction in which any which plus channel three combined to form and A and No. Three equals Plus this. So basically, this is the reaction that is the The products are any Ohh less H and R three equals. So that will form any and no three equals. And this is etched toe all liquid. So the missing product is actually good. Missing product is edge to a liquid, and this is the balanced equation, and this is the double exchange reaction. This is the double exchange reaction. So reaction in the part a reaction one in party is the double exchange reaction. Now coming to the part B, that is C two H four, see toe edge four. So basically, this is 18 so 18 when combined with chlorine gas and the product form these So when you think that it&#x27;s C two h four combined with glory in gales, the product for Miss C toe H four c l to guess so the missing product is missing. Product is see toe edge four C l two and this is a combination reaction. This is a combination reaction because in the combination reaction two or more react and combined to form a single product So which is shown by this reaction now coming toe the part c off the reaction which is chlorine gas when it is combined with the magnesium bromide, MGB are too solid. So it it converts into b R two solid and this missing product. So in this case, So this is the C l two chlorine guests. When combined with the magnesium bromide in the solid form, it converts him toe Romy in the solid form plus M gcl too, because the possible product from this reaction is only m BCL two solid. So that means missing product in this reaction is m gcl too. And this is the single exchange reaction. This is a single exchange. This is the single exchange reaction. So these are the these are the balanced equation also, and we can also we identify the missing product and we also discuss about the types off reactions

Sam Limsuwannarot · Answer

the question here wants us to identify. The reaction has come. Combination decomposition, replacement or combustion. So for a here, we know that aluminum offside is basically broken down. And this is going to be a decomposition reaction for B here. We have a replacement reaction for C here. We also have an example of a replacement on reaction, but is going to be a single one for D here. We know that we are going to have a replacement reaction on for me here. We have a combination reaction.

Sam Limsuwannarot · Answer

question here wants us to classify What type of reaction occurs in the following. So for a here, we&#x27;re gonna have a combination reaction for B here. We are going to have a replacement reaction. First. He here we are going to get a decomposition reaction. Um, for D here, we are going to get a single replacement reaction on for a year. We aren&#x27;t going to get another replacement reaction.

Sam Limsuwannarot · Answer

So the questioner wants us to classify the flying reaction. So for a year, we&#x27;re going to get a combination reaction for be here. We&#x27;re going to get a replacement. Reaction, however, is gonna be a single one. Um, for C here, we are going to get a decomposition reaction for D. Here we are going, Teoh, in this particular case case. Rather, we&#x27;re going to get a replacement reaction. And for me, here we are going to get another combustion reaction.

Sam Limsuwannarot · Answer

Russian here wants us to identify the falling reaction. So for a year, we&#x27;re going to get a replacement reaction for Be here. We&#x27;re going to get a combination reaction for See? Here we have a combustion reaction for D here. We have a replacement reaction on. Lastly for me here, we&#x27;re going to get a decomposition reaction.

David Collins · Answer

if we have sodium chloride, undergo electrolysis when we have a decomposition reaction. Little break apart into sodium and chlorine gas. Remember that chlorine gas as a molecule whose die atomic. So we need to put a two years. We have to chlorine. We need to put a two on sodium. Then if we have copper and we have, uh, roaming has a gas combining in a combination reaction, then we&#x27;re going to end up with calcium bromide. And this is already balanced. If you have C two h four, nothing reacting with oxygen producing carbon dioxide and water. This is a an example of a combustion reaction, as was mentioned in the problem. So the balance it we have two carbons we need to carbons here. Now we have, and then we have four hydrogen. So we need four hydrogen tear putting to there and then we end up with four plus 26 oxygen&#x27;s. We need to put a three right there to get six oxygen. Then, if nickel cool ride undergoes a double displacement reaction by reacting with sodium hydroxide will end up with nickel hydroxide. We&#x27;re gonna need to high drop sites here cause nickel has a plus to charge, then sodium chloride, each with a plus one in minus one. Just one of each of them will combine, but now we need to balance it. We have to Corinne&#x27;s so we need to put a to in front of the A C l. When we do that, we now have to sodium. So we need to put it to in front of and a

Problem

List four molecules and four ionic compounds in t…

Problem 3 Easy Difficulty

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