Question
Codeine $\left(\mathrm{C}_{18} \mathrm{H}_{21} \mathrm{NO}_{3}\right)$ is a weak organic base. A $5.0 \times 10^{-3} \mathrm{M}$ solution of codeine has a pH of 9.95. Calculate the value of $K_{b}$ for this substance. What is the $\mathrm{p} K_{b}$ for this base?
Step 1
We have a solution of codeine with a concentration of \( [\text{C}_{18} \text{H}_{21} \text{NO}_{3}] = 5.0 \times 10^{-3} \, \text{M} \) and a pH of 9.95. Show more…
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Codeine $\left(\mathrm{C}_{18} \mathrm{H}_{21} \mathrm{NO}_{3}\right)$ is a weak organic base. $\mathrm{A}$ $5.0 \times 10^{-3} \mathrm{M}$ solution of codeine has a pH of 9.95. Calculate the value of $K_{b}$ for this substance. What is the $\mathrm{p} K_{b}$ for this base?
codeine $\left(\mathrm{C}_{18} \mathrm{H}_{21} \mathrm{NO}_{3}\right)$ is a weak organic base. $\mathrm{A} 5.0 \times 10^{-3} \mathrm{M}$ solution of codeine has a pH of $9.95 .$ Calculate the value of $K_{b}$ for this substance. What is the $\mathrm{pK}_{b}$ for this base?
Codeine (C18H21NO3) is a weak organic base. A 5.0Ă—10^-3 M solution of codeine has a pH of 9.95. Calculate the value of Kb for this substance.
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