00:01
Let us solve this match the following problem.
00:04
Let's see part a.
00:06
In part a, 2 plus i root 3 is a root of a bi -quodratic equation x -par4 minus 4 x squared plus 8x plus 35 equal to 0.
00:19
Now, if you can notice the coefficients of this polynomial are real.
00:26
Remember, if the coefficients of polynomial are real, then, complex roots occurs in conjugate pairs.
00:36
So that means what is the conjugate of 2 plus i root 3? it is 2 minus i root 3.
00:40
So 2 minus i root 3 is also a root of the above polynomial equation.
00:49
So 2 plus i root 3, 2 minus i root 3.
00:53
Both the values are the roots of this.
00:57
Now by quantity roots there should be 4 but we got it as 2.
01:02
We got only 2 root 3.
01:04
We got only 2 root 3.
01:04
This and this.
01:05
So how to find the other two roots? so let's see how to find the other two roots.
01:10
So when 2 plus i root 3 is a root x minus of 2 plus i root 3 is a factor...