00:01
In this question, we need to match the elements of column 1 with the elements of column 2.
00:07
In part a, we need to find the value of alpha to the power 1001 plus alpha to the power 1002 plus so on plus alpha to the power 230.
00:32
And it is given that x to the power 5 is equal to 1.
00:40
And alpha is not equals to 0.
00:48
Now since x to the power 5 is equal to 1, therefore we can write alpha to the power 5 is equals to 1.
01:02
Hence alpha to the power 101 plus alpha to the power 102 plus so on plus alpha to the power 230 will be equal to the power 1002 plus so on plus alpha to the power 230 will be equal.
01:18
Equals to alpha to 2 the power 101 into 1 minus alpha to the power 130 upon 1 minus alpha and this will be equals to alpha to the power 101 into 1 minus alpha to the power 5 to the power 26 upon 1 minus alpha and this will be equals to 0.
01:55
Hence the correct match is a with p so this is the first correct match now come to point b in part b we need to find the maximum and minimum value of modulus z where that represents the curve z is equals to 3 upon 2 plus cos theta plus iota sine theta since z represents a complex number and z is equals to x plus iota y therefore we can write the above equation as x plus iota y is equal 2 plus cos theta plus iota sine theta and this expression can also be written as 1 upon x plus iota y is equal to 2 plus cos theta plus iota sine theta upon 3 and this will be equals to x minus iota y upon x square plus y square is equal to 2 plus cos theta plus iota sine theta upon 3 now equate the real parts real parts we get x upon x upon x square plus y square is equal to 2 plus cos theta upon 3.
04:51
Therefore, cost theta is equal to 3x upon x square plus y square minus 2.
05:08
Similarly equate the imaginary parts.
05:18
Parts we get minus y upon x square plus y square is equal to sine theta upon three or we can write sine theta is equal to minus three y upon x square plus y square since sine square t, plus cos squared theta is equal to 1.
06:09
Therefore, from the values of sine theta and cost theta, we can write 3x upon x square plus y square minus 2 to the power 2 plus 3y upon x square plus y square to the power 2 is to 1 and this will be equals to 9 x square upon x square plus y square to the power 2 plus 9 y square upon x square plus y square to the power 2 minus 12 x square upon x square plus y square plus 4 is equal to 1.
07:14
When we further solve it we get x minus 2 plus y square is equal to 1.
07:29
This is a equation of circle whose center is 2 .0 and the radius is 1.
07:56
We can make this circle as shown below.
08:06
In this circle, this point is 1, this point is 3 and this is the center 2 .0.
08:18
Therefore we can conclude that the maximum value of modulus z is equals to 3 and the minimum value of modulus is equal to 1.
08:35
Hence the correct match is b and s q.
08:46
This is the correct answer for option b...