00:01
In this problem, we need to answer three different questions regarding the relationship between the standard cell potential and temperature.
00:09
We are first given these two equations for the change in gibbs free energy at standard conditions, and we need to combine them and rearrange them in order to derive an expression for the standard cell potential as a function of temperature.
00:21
So since we know that our derived equation needs to be one for finding the standard cell potential, and that the standard cell potential only appears in this equation, it's reasonable to assume that we should begin by isolating that term from that first equation.
00:39
So the standard cell potential, e, is equal to delta g at standard conditions divided by negative nf, and that's just from rearranging that first equation that we are given.
00:53
And now we see that the second equation gives us an expression for delta g at standard conditions that we can substitute into the numerator of that rearranged expression from the first equation.
01:03
So when we substitute that in, the numerator now becomes delta h at standard conditions minus t, delta s at standard conditions, divided by negative nf.
01:16
And the next part of this question asks us how we can determine the values of delta h and delta s at standard conditions if we have values, experimental values, that we can measure for the and the cell potential.
01:32
And in order to determine these values graphically, we need to rearrange our derived expression for the standard cell potential as a function of temperature to form the equation of a line so that we can easily see how when we graph out those two values that is the temperature and the cell potential, knowing that temperature is the x variable and cell potential is the dependent y variable.
02:04
And so we know the equation of a line, y equals mx plus b, and so we can rearrange our derived expression in order to find that form of that graphical line equation.
02:16
So the standard cell potential is equal to delta s at standard conditions divided by nf times the temperature minus delta h.
02:35
At standard conditions over nf.
02:39
And again, this was just done by further simplifying our expression for cell potential as a function of temperature.
02:48
We did negative t delta s divided by negative nf to give us positive s over nf, and we left temperature out there since we know that that is our independent variable in the equation of a line and therefore corresponds to x in the general form of a line, y equals mx plus b.
03:04
And then we also did delta h divided by negative nf, which is minus delta h over nf.
03:16
So now we can see that we have a form of a line, why the dependent variable of cell potential at standard conditions is equal to m times x, which is a temperature independent variable plus b...