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Manhattan College
Problem 98

Combustion analysis of naphthalene, a hydrocarbon used in mothballs, produces 8.80 $\mathrm{g} \mathrm{CO}_{2}$ and 1.44 $\mathrm{g} \mathrm{H}_{2} \mathrm{O} .$ Calculate the empirical formula of naphthalene.

$\mathrm{C}_{5} \mathrm{H}_{4}$

Chapter 3
Molecules, Compounds, and Chemical Equations
Chemistry A Molecular Approach

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## Video Transcript

All right, guys, We're doing problem. Number engaged of chapter three B in chemistry to molecular approach. Combustion house is in apple in a hydrocarbon used in mob. All purchases 8.8 is your O gram Seiko two and 1.44 This is it. I'm going for four grams, actually, the empirical formula pineapple plane. So we're going to take the mass of our CEO, too, and we're gonna multiply by a ratio issue of the mass of of the molecular weight of carbon over the milk. What a carbon dioxide carbon is 12. Carbon dioxide is 44. That's gonna give us our mass percentage. This is gonna be the mass percentage of carbon. So that fraction multiply by the overall mass will give us just the mass of our carbon gonna be equal 2.44 grams carbon and for water one point for four grands times to over 18. Mating too. Because we Each hadron is a molecular weight of one gram per mole and we have two engine, so that's gonna be equal to zero 0.16 gramps. And next we're gonna convert this. Two moles. 2.442 point four grams guys, one more per 12 grams equals zero 0.2 moles. So zero 21 6 grams. That's one more. Her one grand, 0.16 moles. So now we're gonna to do the empirical formula, we're gonna divide each by the least number of moles. That's gonna be zero 0.2 over 0.16 This allows to find the ratio of carbon do hydrogen 1.2 bye. And this one's gonna be to your 0.16 over 0.16 which is equal to one. And as you can probably understand, you can't have 1.25 five carbon atoms because you can't have a fraction of a car. But I'm gonna leave. It's either and Adam where it is. So we're gonna multiple. We're going to get us to it as, uh, next hole number. So we're gonna multiply everything by four. So 1.255 times for that's gonna be five. You have one time for its going before. That means our empirical formula is gonna be C five age for, And that's not how we do. You just have to understand how these different equation equations work. You have to understand how to relate the mass percent to the massive CIA to mass massive order. And then I understand I had to find your empirical formula.