Question
Compare the density of helium to the density of air at a pressure of $101 \mathrm{kPa}$ and a temperature of $25^{\circ} \mathrm{C}$. What are the specific volumes of these two gases at the given temperature and pressure?
Step 1
The formula for density is given by: \[ \rho = \frac{P}{RT} \] where: - $\rho$ is the density, - $P$ is the pressure, - $R$ is the molar gas constant, and - $T$ is the temperature. Show more…
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If a pipe contains helium at a gage pressure of $100 \mathrm{kPa}$ and a temperature of $20^{\circ} \mathrm{C}$, determine the density of the helium. Also, determine the temperature if the helium is compressed isentropically to a gage pressure of $250 \mathrm{kPa}$. The atmospheric pressure is $101.3 \mathrm{kPa}$.
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The density of gaseous helium at $25^{\circ} \mathrm{C}$ and normal atmospheric pressure is $1.64 \times 10^{-4} \mathrm{~g} / \mathrm{mL}$. At the same temperature and pressure the density of argon gas is $1.63 \times 10^{-3} \mathrm{~g} / \mathrm{mL}$. The mass of an atom of argon is almost exactly ten times the mass of an atom of helium. Provide a nanoscale explanation of why the densities differ as they do.
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