00:01
For this problem on the topic of inductance, we are given an introduction into the mazner effect, and we are told to consider a vertical solenoid that has a length of 120 centimeters and a diameter of 2 .5 centimeters.
00:13
It consists of copper wire with 1 ,400 turns carrying a current in the counterclockwise direction of 2 ampiers, as shown in the figure.
00:23
We want to solve for various quantities of the solenoid.
00:30
Firstly, we want to find the magnetic field in the vacuum inside the solenoid.
00:36
Now we know the magnetic field b is equal to mu knot times n times i divided by l.
00:47
And this is the magnetic constant mu not, which is 4 pi times 10 to the minus 7 tesla meter per ampere multiplied by the number of turns in the wire, which is 1 ,000.
01:02
400 times the current of 2 amperes divided by the length 1 .2 meters.
01:14
So this gives us the magnetic field to be 2 .93 times 10 to the minus 3 teslers.
01:30
And the right hand rule gives us the direction, which is upward.
01:34
So that's the magnetic field inside the solenoid.
01:42
For part b of the problem, we want to find the energy density of the magnetic field.
01:50
Now the energy density is given by u, and we know u is the magnetic field strength squared, which is b squared over 2 times mu not.
02:00
So now that we have the magnetic field, we can calculate this energy density.
02:04
This is to 0 .93 times 10 to the minus 3 tesla's.
02:10
As calculated above, squared, divided by two times the emignetic constant, 4 pi times 10 to the minus 7, tesla meter per ampere, which gives us the energy density to be 3 .42 joules per cubic meter, which is equivalent to 3 .42 pascels.
02:52
In part c of this problem, we are told that a source superconducting bar that has a diameter of 2 .2 centimeters is inserted partway into the solenoid...