00:01
For the first problem, let's try to explain that y, y1 is equal to e to the power x plus c1, and y2 is equal to c times e to the power x as anti -derivative, as anti -derivative are equivalent expression.
00:26
So let's start with y1.
00:28
Y -1 is equal to e to the power x plus c -1.
00:31
That can be written as e to the power x followed by e to the power c1, which is same as e to the power c1 times e to the power x.
00:41
Now, i know that c1 is a constant.
00:47
So this implies that e to the power c1 is also an constant, a constant.
00:57
So this means i can replace this e to the power c1 by a different constant.
01:03
Constant c so that means this expression y1 is equal to e to the per c1 times c to the power x can be re -reten as some different constant c times e to the power x which is exactly my second expression y2 is equal to c times c to the power x so this implies that both y1 and y2 are equivalent.
01:39
So for the second problem, it's a bit tricky...