Problem

Write a balanced equation for each of the followi…

01:42

Problem 14 Medium Difficulty

Complete each of the following equations:
(a) $\frac{7}{3} \mathrm{Li}+? \longrightarrow 2_{2}^{4} \mathrm{He}$
(b) $14 \mathrm{C} \longrightarrow^{14} \mathrm{N}+?$
(c) $27 \mathrm{Al}+_{2}^{4} \mathrm{He} \longrightarrow ?+_{0}^{1} \mathrm{n}$
(d) $_{96}^{250} \mathrm{Cm} \longrightarrow 2+_{38}^{98} \mathrm{Sr}+4_{0}^{1} \mathrm{n}$

Answer

a) $_{3}^{7} \mathrm{Li}+_{1}^{1} \mathrm{H} \rightarrow 2_{2}^{4} \mathrm{He}$
b) $_{6}^{14} \mathrm{C} \rightarrow_{7}^{14} \mathrm{N}+_{-1}^{0} \mathrm{e}$
c) $_{13}^{27} \mathrm{Al}+_{2}^{4} \mathrm{He} \rightarrow_{15}^{30} \mathrm{P}+_{0}^{1} \mathrm{n}$
d) $_{96}^{250} \mathrm{Cm} \rightarrow_{58}^{148} \mathrm{Ce}+_{38}^{98} \mathrm{Sr}+_{0}^{1} \mathrm{n}$

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Video Transcript

your reaction are the reaction in which nucleus off one element convert into nucleus off other element. There are two types off reactions vision, in which the unstable nuclear off element breaks in tow to lighter, lighter considering and vision in which to nuclear combines to form a larger nucleus. The law off Conservation Off Mar states that the summer off masses off the reactant is equal to the sum off total mass off product. The Law of conservation off Jane states that the some off change on on the reactor inside is equal. Do some off charges On the broader TSE days, atomic mass is some off number off Paradorn. A number off Paradorn present in an element but a on the right hand side, the some off Mars off productive 8 a.m. U. The some off atomic number is four on react. Inside. Lee Tim is given whose masses 70 EMU on atomic number history. Using the falling laws we can. They don't mean the some off charges on the reactant side that turns out to be one. Similarly, the some off mass on the reactions I can be can be distracted as one for part B on the right hand side, the some off masses off the reacting this 14 am you on some off atomic number is six. By falling the laws off conservation and charge, the atomic number on atomic mass off unknown element can be calculated. A shown over here, the some off charges on the reactions. I don't know, Toby minus one. Buy me some off mark. It's under the act inside turns out to be zeal for boxy on the right. Inside this, some off masses off react inside is it is equal to 31 a. M. U. While atomic number is 15 on the product size, only one neutron is given. Who's Moss is one AM you on, judge? Is zero falling The law of conservation off mass on charges we can determine dough some off charges. On the reactant side, that is 15 while some off mass on the reactant Cy is 30 for last part body on the right. Inside the some off masses off unknown reactant is 102 a. M. You, while the some off atomic number is 38. By falling the law of conservation off mass and charge the atomic number an atomic mass off unknown element can be calculated as shown this some off judges on react inside turns out to be 58. The some off masses on the the act inside gives us 100 and 48 a. M. U.

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