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Complete each solution.$$\begin{aligned}(2 x+5)(3 x-2) &=2 x(3 x)-\quad(2)+\quad(3 x)-(2) \\&=6 x^{2}-\quad+10 \\&=6 x^{2}+\quad-10\end{aligned}$$
$2 x, 5,5,4 x, 15 x, 11 x$
Algebra
Chapter 5
Exponents and Polynomials
Section 6
Multiplying Polynomials
Polynomials
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Baylor University
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complete the solution by filling in the blanks. You have the product of two by no meals, so we can use foil. The product of the first terms to x Times three x minus The product of the last terms two x times two plus The product of the inner terms five times three x minus The product of five and two This gives US six X squared minus for X plus 15 x minus 10 to combine like terms. Would add that negative for X to 15 x, with a final answer of six X squared plus 11 x minus 10.
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